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3 years ago

5

What type of soruce is the sun

1 answer:

NemiM [27]3 years ago

7 0

Answer:

Light source

Explanation:

The Sun is a light source because it releases energy from inside itself. The Moon isn't a light source. It doesn't produce energy inside itself, and instead just reflects light from the Sun.

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in positive numbers less than 1, the zeros between the decimal point and non zero are _____ significant

Margaret [11]

Zeros the left of the decimal but still less than one are non significant but to the right they are.
For example: 0.003 (only 3 is significant) but for 0.030 (two are significant)

8 0

3 years ago

A railroad car of mass 3.45 ✕ 104 kg moving at 2.60 m/s collides and couples with two coupled railroad cars, each of the same ma

Alex

Answer:

a) 1.67 m/s

b) 23kJ

Explanation:

We need to apply the linear momentum conservation formula, that states:

$m1*v_{o1}+m2*v_{o2}=m1*v_{f1}+m2*v_{f2}$

in this case:

$3.45*10^4kg*2.60m/s+2*3.45*10^4kg*1.20m/s=3*m1*v_{f}\\v_f=1.67m/s$

the initital kinetic energy is:

$K_i=\frac{1}{2}*3.45*10^4kg*(2.60m/s)^2+2(\frac{1}{2}*3.45*10^4kg*(1.20m/s)^2\\K_i=167kJ$

and the final:

$K_f=3*\frac{1}{2}*3.45*10^4kg*(1.67m/s)^2\\K_f=144kJ$

The energy lost is given by:

$E_l=|K_f-K_i|\\E_l=23kJ$

8 0

3 years ago

Toon Train is traveling at the speed of 10 m/s at the top of a hill. Five seconds later it reaches the bottom of the hill and is

Naddika [18.5K]

Answer:

the rate of acceleration of the train is 4 m/s²

Explanation:

Given;

initial velocity of the train, u = 10 m/s

change in time of motion, dt = 5 s

final velocity of the train, v = 30 m/s

The rate of acceleration of the train is calculated as;

$a = \frac{dv}{dt} = \frac{v-u}{dt} = \frac{30-10}{5} = \frac{20}{5} = 4 \ m/s^2$

Therefore, the rate of acceleration of the train is 4 m/s²

5 0

3 years ago

A quantity of 14.1 cm^3 of water at 8.4°C is placed in a freezer compartment and allowed to freeze to solid ice at -7.2°C. How m

serious [3.7K]

Answer:920.31 J

Explanation:

Given

Volume of water (V) $=14.1 cm^3$

mass(m) $=\rho \times V=1000\times 14.1\times 10^{-6}=14.1 gm$

Temperature $=8.4^{\circ} C$

Final Temperature $=-7.2 ^{\circ}C$

specific heat of water(c) $=4.184 J/g-^{\circ}C$

Therefore heat required to removed is

$Q=mc(\Delta T)$

$Q=14.1\times 4.184\times (8.4-(-7.2))$

$Q=920.31 J$

3 0

4 years ago

1. When asteroids collided some of the broken materials fall into Earth's orbit. What do

Kazeer [188]

I believe it is meteoroids

6 0

3 years ago

Read 2 more answers