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3 years ago

How do p-wave and S-wave differ?

Physics

1 answer:

oksian1 [2.3K]3 years ago

3 0

Answer:

P wave has pee lol just kidding one of them transmit more sound or intrections than the other

Explanation:

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Professional Application: A 30,000-kg freight car is coasting at 0.850 m/s with negligible friction under a hopper that dumps 11

Nataliya [291]

Answer:

0.182 m/s

Explanation:

m1 = 30,000 kg, m2 = 110,000 kg, u1 = 0.85 m/s

let the velocity of loaded freight car is v

Use the conservation of momentum

m1 x u1 + m2 x 0 = (m1 + m2) x v

30,000 x 0.85 = (30,000 + 110,000) x v

v = 0.182 m/s

5 0

3 years ago

Solve for A if F=MA and F=100 and M=25?

inn [45]

Answer:

<h3> $\boxed{ \boxed{ \bold{A = 4}}}$ </h3>

Explanation:

Given,

F = 100 , M = 25

Now, let's find the value of A

$\sf{F = MA}$

plug the values

⇒ $\sf{100 = 25 A}$

Swap the sides of the equation

⇒ $\sf{25A = 100}$

Divide both sides of the equation by 25

⇒ $\sf{ \frac{25A}{25} = \frac{100}{25} }$

Calculate

⇒ $\sf{A = 4}$

Hope I helped!

Best regards!!

5 0

3 years ago

Read 2 more answers

How is wind energy converted into electrical energy.

Lynna [10]

Wind turbines take the kinetic energy from the wind and convert it into mechanical energy which can be used for different stuff such as a generator which converts it into electrical energy.
Have a wonderful day!

4 0

3 years ago

In an experiment of a simple pendulum, measurements show that the pendulum has length し 0.397 ± 0.006 m, mass M-0.3172 ± 0.0002

vichka [17]

Answer:

1.)1.265+or minus 0.0006m

2).0.71%

Explanation:

See attached file

6 0

3 years ago

Two blocks on a frictionless horizontal surface are on a collision course. one block with mass 0.6 kg moves at 0.8 m/s to the ri

Elanso [62]

First we can say that since there is no external force on this system so momentum is always conserved.

$m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}$

$0.6*0.8 + 1.2*0 = 0.6*v_{1f} + 1.2*v_{2f}$

$0.48= 0.6*v_{1f} + 1.2*v_{2f}$

$0.8 = v_{1f} + 2v_{2f}$

now by the condition of elastic collision

$v_{2f} - v_{1f} = 0.8 - 0[\tex]now add two equations[tex]3*v_{2f} = 1.6$

$v_{2f} = 0.533 m/s$

also from above equation we have

$v_{1f} = -0.267 m/s$

So ball of mass 0.6 kg will rebound back with speed 0.267 m/s and ball of mass 1.2 kg will go forwards with speed 0.533 m/s.

8 0

3 years ago