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kozerog [31]
4 years ago
8

Find the area between the graph of the function and the x-axis over the given interval, if possible.

Mathematics
1 answer:
vodomira [7]4 years ago
7 0

Answer:

A= -\frac{5}{-1} - \lim_{x\to\infty} \frac{5}{x-2} = 5-0 = 5

So then the integral converges and the area below the curve and the x axis would be 5.

Step-by-step explanation:

In order to calculate the area between the function and the x axis we need to solve the following integral:

A = \int_{-\infty}^1 \frac{5}{(x-2)^2}

For this case we can use the following substitution u = x-2 and we have dx = du

A = \int_{a}^b \frac{5}{u^2} du = 5\int_{a}^b u^{-2}du

And if we solve the integral we got:

A= -\frac{5}{u} \Big|_a^b

And we can rewrite the expression again in terms of x and we got:

A = -\frac{5}{x-2} \Big|_{-\infty}^1

And we can solve this using the fundamental theorem of calculus like this:

A= -\frac{5}{-1} - \lim_{x\to\infty} \frac{5}{x-2} = 5-0 = 5

So then the integral converges and the area below the curve and the x axis would be 5.

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3 years ago
If f(x)=x squared-2x and g(x) = 6x+4 for which is a value of x does (f+g)(x) =0
ra1l [238]

Answer:

For x = -2

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}

x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}

\Delta = b^{2} - 4ac

In this question:

f(x) = x^2 - 2x

g(x) = 6x + 4

f(x) + g(x) = (f+g)(x)  = x^2 - 2x + 6x + 4 = x^2 + 4x + 4

Which is a value of x does (f+g)(x) =0

x^2 + 4x + 4

Quadratic equation with a = 1, b = 4, c = 4

So

\Delta = 4^{2} - 4*1*4 = 0

x_{1} = \frac{-4 + \sqrt{0}}{2} = -2

x_{2} = \frac{-4 - \sqrt{0}}{2} = -2

For x = -2

7 0
3 years ago
Please answer this question i really need your help
navik [9.2K]
Functions:graph B,mapping A, Table B
Grape B is a function because it passes the vertical line test ( meaning when I draw a vertical line any where on the graph the line only touched one point),mapping A is a function because each x value has only one y value same with table.
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Graph A does not pass vertical line test so it is not a function, mapping B and Table A both have an x value that has two y values and that is not a function.
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Step-by-step explanation:

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Step-by-step explanation:

6(1 - 8m) + 3m = 231

6 - 48m + 3m = 231

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3 years ago
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