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kozerog [31]
3 years ago
8

Find the area between the graph of the function and the x-axis over the given interval, if possible.

Mathematics
1 answer:
vodomira [7]3 years ago
7 0

Answer:

A= -\frac{5}{-1} - \lim_{x\to\infty} \frac{5}{x-2} = 5-0 = 5

So then the integral converges and the area below the curve and the x axis would be 5.

Step-by-step explanation:

In order to calculate the area between the function and the x axis we need to solve the following integral:

A = \int_{-\infty}^1 \frac{5}{(x-2)^2}

For this case we can use the following substitution u = x-2 and we have dx = du

A = \int_{a}^b \frac{5}{u^2} du = 5\int_{a}^b u^{-2}du

And if we solve the integral we got:

A= -\frac{5}{u} \Big|_a^b

And we can rewrite the expression again in terms of x and we got:

A = -\frac{5}{x-2} \Big|_{-\infty}^1

And we can solve this using the fundamental theorem of calculus like this:

A= -\frac{5}{-1} - \lim_{x\to\infty} \frac{5}{x-2} = 5-0 = 5

So then the integral converges and the area below the curve and the x axis would be 5.

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lutik1710 [3]
Firstly, for it to be a trinomial the expression would have to be x^2+5x+6 to factor this we would simply have to find 2 numbers that add up to 5 and multiply to 6. 3+2=5 and 3•2=6 so (x+3)(x+2) would be the answer
5 0
3 years ago
EVERYONE GO GIVE DRAZOAVANS1 A BRAINLIEST PLZZZZZ!!!!
GaryK [48]

Answer:

we can only give brainliest if we ourselves have asked the a question ( to which she/he answered)

3 0
3 years ago
A superhero asked his nemesis how many cats she has. she answered with a riddle "Three-fourths of my cats plus seven" how many c
liq [111]
Let C be the number of cats of the superhero. With this, the number of cats of nemesis have is 3C/4 + 7. The numbers should be equal such that,
                                     C = 3C/4 + 7
The value of C from the equation is 28. Thus, the number of cats of the nemesis is 28. 
6 0
3 years ago
A theater group made appearances into cities the hotel charge before tax and the second city was 1500 higher than the first the
Svetlanka [38]

Answer:

The hotel charge in each city before tax was <u>$5125</u> of the first city and <u>$3625</u> of the second city.

Step-by-step explanation:

Given:

A theater group made appearances into cities the hotel charge before tax and the second city was 1500 higher than the first.

The tax of the first city was 6% and the tax of the second city was 10%.

Total hotel tax paid for two cities with $670.

Now, to find the hotel charge in each city before tax.

Let the hotel charge in first city before tax be x.

And the hotel charge in second city before tax be y.

<em>So, as the hotel charge of the second city was 1500 higher than the first.</em>

<em>Thus</em>,

y=x-1500   ........(1)

<em>And as given, the tax of the first city was 6% and the tax of the second city was 10%, total hotel tax paid for two cities with $670.</em>

6% of x + 10% of y = $670.

\frac{6x}{100} +\frac{10y}{100} =670

0.06x+0.10y=670

Substituting the value of y from equation (1) we get:

0.06x+0.10(x-1500)=670

0.06x+0.10x-150=670

0.16x-150=670

<em>Adding both sides by 150 we get:</em>

0.16x=820

<em>Dividing both sides by 0.16 we get:</em>

x=5125.

<em>The hotel charge in first city before tax = $5125.</em>

Now, substituting the value of x in equation (1) we get:

y=x-1500

y=5125-1500

y=3625.

<em>The hotel charge in second city before tax = $3625.</em>

Therefore, the hotel charge in each city before tax was $5125 of the first city and $3625 of the second city.

5 0
3 years ago
Fam what is 25 x 25 please help me fam needd the answer ASAP!
Vlada [557]

Answer:

it is 625

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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