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kozerog [31]
4 years ago
8

Find the area between the graph of the function and the x-axis over the given interval, if possible.

Mathematics
1 answer:
vodomira [7]4 years ago
7 0

Answer:

A= -\frac{5}{-1} - \lim_{x\to\infty} \frac{5}{x-2} = 5-0 = 5

So then the integral converges and the area below the curve and the x axis would be 5.

Step-by-step explanation:

In order to calculate the area between the function and the x axis we need to solve the following integral:

A = \int_{-\infty}^1 \frac{5}{(x-2)^2}

For this case we can use the following substitution u = x-2 and we have dx = du

A = \int_{a}^b \frac{5}{u^2} du = 5\int_{a}^b u^{-2}du

And if we solve the integral we got:

A= -\frac{5}{u} \Big|_a^b

And we can rewrite the expression again in terms of x and we got:

A = -\frac{5}{x-2} \Big|_{-\infty}^1

And we can solve this using the fundamental theorem of calculus like this:

A= -\frac{5}{-1} - \lim_{x\to\infty} \frac{5}{x-2} = 5-0 = 5

So then the integral converges and the area below the curve and the x axis would be 5.

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We conclude that:

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Step-by-step explanation:

Given the expression

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solving

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Scalar Multiplication: Multiply each of the matrix elements by a scalar

=\begin{pmatrix}3\cdot \:2\left(-2\right)&3\cdot \:2\cdot \:3&3\cdot \:2\cdot \:0\\ 3\cdot \:2\left(-4\right)&3\cdot \:2\cdot \:2&3\cdot \:2\cdot \:6\\ 3\cdot \:2\cdot \:6&3\cdot \:2\left(-5\right)&3\cdot \:2\cdot \:6\end{pmatrix}

Simplify each element

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3\cdot \:2\begin{pmatrix}-2&3&0\\ -4&2&6\\ 6&-5&6\end{pmatrix}=\begin{pmatrix}-12&18&0\\ -24&12&36\\ 36&-30&36\end{pmatrix}

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