Answer:
B. 6HgO → 6Hg + 3O
Explanation:
A decomposition reaction is a reaction in which a single reactant is broken down into 2 or more products.
★ A grey hound pursues a hare and takes 5 leaps for every 6 leaps of the hare, but 3 leaps of the hound are equal to 5 leaps of the hare.
★ The speed of the hound and the hare
★ The speed of the hound and the hare = 25:18
As it's given that a grey hound pursues a hare and takes 5 leaps for every 6 leaps of the hare, but 3 leaps of the hound are equal to 5 leaps of the hare.
So firstly let us assume a metres as the distance covered by the hare in one leap.
Ok now let's talk about 5 leaps,.! As it's cleared that the hare cover the distance of 5a metres.
But 3 leaps of the hound are equal to 5 leaps of the hare.
Henceforth, (5/3)a meters is the distance that is covered by the hound.
Now according to the question,
Hound pursues a hare and takes 5 leaps for every 6 leaps of the hare..! (Same interval)
Now the distance travelled by the hound in it's 5 leaps..!
Now the distance travelled by the hare in it's 6 leaps..!
Now let us compare the speed of the hound and the hare. Let us calculate them in the form of ratio..!
Answer:
I beleive it would shoot very far up into the sky
Explanation:
Given Information:
slope angle = θ = 30°
spring constant = k = 30 N/m
compressed length = x = 10 cm = 0.10 m
mass of ice cube = m = 63 g = 0.063 kg
Required Information:
distance traveled by ice cube = d = ?
Answer:
distance traveled by ice cube = 0.48 m
Explanation:
Using the the principle of conversation of energy, the following relation holds true for this case,
mgh = 1/2*kx²
h = 1/2*kx²/mg
Where h is the height of the slope, m is the mass of ice cube, k is the spring constant and x is the compressed length o the spring and g is gravitational acceleration.
h = 1/2*kx²/mg
h = 1/2*30(0.1)²/0.063*9.8
h = 0.242 m
From trigonometry ratio,
sinθ = h/d
d = h/sinθ
d = 0.242/sin(30)
d = 0.48 m
Therefore, when the ice cube is released, it will travel a total distance 0.48 up the slope before reversing direction.