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3 years ago

7

In a car with a mass of 4,000 KG is accelerating at a rate of 2m/s2 and hits a tree what force does it have

1 answer:

Ilia_Sergeevich [38]3 years ago

3 0

According to Newton's second law of motion, the acceleration of a body is directly proportional to the force acting on the body and inversely proportional to its mass. The formula for this law is

F=ma

=4000kg * 2m/s 2 =8000N

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Topic: Chapter 10: Projectory or trajectile?

Charra [1.4K]

Answer:

The other angle is 75⁰

Explanation:

Given;

velocity of the projectile, v = 10 m/s

range of the projectile, R = 5.1 m

angle of projection, 15⁰

The range of a projectile is given as;

$R = \frac{u^2sin(2\theta)}{g}$

To find another angle of projection to give the same range;

$5.1 = \frac{10^2 sin(2\theta)}{9.81} \\\\100sin(2\theta) = 50\\\\sin(2\theta) = 0.5\\\\2\theta = sin^{-1}(0.5)\\\\2\theta = 30^0\\\\\theta = 15^0\\\\since \ the \ angle \ occurs \ in \ \ the \ first \ quadrant,\ the \ equivalent \ angle \\ is \ calculated \ as;\\\\90- \theta = 15^0\\\\\theta = 90 - 15^0\\\\\theta = 75^0$

<u>Check: </u>

sin(2θ) = sin(2 x 75) = sin(150) = 0.5

sin(2θ) = sin(2 x 15) = sin(30) = 0.5

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2 years ago

What is the x component of (+3m)ι^ And (+3m/s) i^?

expeople1 [14]

The "i" component of a vector is in the x-direction. Therefore, the x-component is 3 m/s.

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3 years ago

Constructive interference will cause two sound waves to cancel each other out resulting in silence

photoshop1234 [79]

It is true that constructive interference will cause two sound waves to cancel each other out resulting in silence.

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3 years ago

Find an expression for the acceleration a of the red block after it is released. use mr for the mass of the red block, mg for th

Drupady [299]

<span>Assuming pulley is frictionless. Let the tension be ‘T’. See equation below.</span>

<span> </span>

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3 years ago

Read 2 more answers

A particle of mass 10 g and charge 72 μC moves through a uniform magnetic field, in a region where the free-fall acceleration is

sineoko [7]

Answer:

$-0.07163\hat k\ T$ or 0.07163 T into the page

Explanation:

m = Mass of particle = 10 g

a = Acceleration due to gravity = -9.8j m/s²

v = Velocity of particle = 19i km/s

q = Charge of particle = 72 μC

B = Magnetic field

Here the magnetic and gravitational forces on the particle are applied in the opposite direction so,

$F_b=F_g$

$F_b=qvBsin\theta\\\Rightarrow F_b=qvBsin90\\\Rightarrow F_b=72\times 10^{-6}\times 19000B$

$F_g=ma\\\Rightarrow F_g=0.01\times -9.8$

$72\times 10^{-6}\times 19000B=0.01\times -9.8\\\Rightarrow B=\frac{0.01\times -9.8}{72\times 10^{-6}\times 19000}\\\Rightarrow B=-0.07163\hat k\ T$

The magnetic field is 0.07163 T into the page

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3 years ago