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klasskru [66]
4 years ago
13

What was the experiment carried out by Hershel & Ritter.

Physics
1 answer:
just olya [345]4 years ago
3 0
Hershel discovered something called Infrared light. It was basically an experiment outdoors and you have a light and when the light hits another surface (like a deck) then that surface heats up 
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There are four springs stretched by the same mass. Spring A stretches 25 cm. Spring B stretches 10 cm. Spring C stretches 100 cm
saul85 [17]

Answer:

spring D stretches the weakest

6 0
3 years ago
An oceanic depth-sounding vessel surveys the
IgorC [24]
So you would divide 1530 by 8 and that’s how you’d get your answer, so it should be (blank)m
3 0
4 years ago
A ball is shot from the ground straight up into the air with initial velocity of 42 ft/sec. Assuming that the air resistance can
Volgvan

Answer:

Maximum height of the ball, h(t) = 27.56 m

Explanation:

It is given that, a ball is shot from the ground straight up into the air with initial velocity of 42 ft/sec.      

The height of the ball as a function of time t is given by :

h(t)=h_o+v_ot-16t^2

h₀ is initial height, h₀ = 0

So, h(t)=42t-16t^2 .........(1)

For maximum/minimum height,  \dfrac{dh(t)}{dt}=0

42-32t=0...(2)

t = 1.31 s

Differentiating equation (2) wrt t

h''(t) = -32 < 0

So, at t = 1.31 seconds we will get the maximum height.

Put the value of t in equation (1)

h(t)=42\times 1.31-16\times (1.31)^2

h(t) = 27.56 m

Hence, this is the required solution.

7 0
4 years ago
A block is at rest. The coefficients of static and kinetic friction are s = 0.81 and k = 0.69, respectively. The acceleration of
lys-0071 [83]

Answer:

Explanation:

a ) The angle required = angle of repose = θ

Tanθ = .81

θ = 39⁰

b ) when angle of incline θ = 44

Net force on the block = mg sinθ - μ mg cosθ where μ is coefficient of kinetic friction

acceleration = gsinθ - μ g cosθ

= 9.8 ( sin44 - μ cos44 )

= 9.8 ( .695 - .69 x .72 )

= 9.8 ( .695 - .497 )

= 1.94 m /s²

7 0
3 years ago
The water behind Grand Coulee Dam is 1000 m wide and 200 m deep. Find the hydrostatic force on the back of the dam. (Hint: the t
Vika [28.1K]

Answer:

The hydro static force on the back of the dam is 1.96\times10^{11}\ N

Explanation:

Given that,

Width b= 1000 m

Depth d= 200 m

We need to calculate the average pressure

Using formula of  average pressure

P_{avg}=\rho\times g\times d_{avg}

Put the value into the formula

P_{avg}=1000\times9.8\times100

P_{avg}=980000\ Pa

We need to calculate  the hydro static force on the back of the dam

Using formula of force

F = P_{avg}\times A

Put the value into the formula

F = 980000\times1000\times200

F=1.96\times10^{11}\ N

Hence, The hydro static force on the back of the dam is 1.96\times10^{11}\ N

7 0
3 years ago
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