Answer:
Explanation:
We shall represent each displacement in vector form .
i will represent east , j will represent north .
D₁ = 4.1 west = - 4.1 i
D₂ = 17.3 north = 17.3 j
D₃ = - 1.2 cos65.4 i + 1.2 sin65.4 j
= - .5 i + 1.09 j
Total displacement
= D₁ + D₂ + D₃
= - 4.1 i + 17.3 j - .5 i + 1.09 j
D = - 4.6 i + 18.39 j
magnitude of D
= √ ( 4.6² + 18.39² )
= √ (21.16 + 338.2 )
= √359.36
= 18.95 km .
Final displacement = 18.95 km .
Answer:
The velocity of charge is 1.1×10⁴
Option(D)
Explanation:
F = q(v×B)
3.5×10-²= (8.4×10-⁴)*(v)*(6.7×10-³)*sin35
v = (3.5)/(8.4×6.7×0.57) × 10⁵
v = 3.5/32.08 × 10⁵
v = 0.109 × 10⁵
v ≈ 1.1 × 10⁴ m/s
KE = 1/2mv^2
KE = 1/2(1000)(20^2)
KE = 2.0 * 10^5
or
KE = 200,000
hope this helps :)
