Explanation:
Assuming the wall is frictionless, there are four forces acting on the ladder.
Weight pulling down at the center of the ladder (mg).
Reaction force pushing to the left at the wall (Rw).
Reaction force pushing up at the foot of the ladder (Rf).
Friction force pushing to the right at the foot of the ladder (Ff).
(a) Calculate the reaction force at the wall.
Take the sum of the moments about the foot of the ladder.
∑τ = Iα
Rw (3.0 sin 60°) − mg (1.5 cos 60°) = 0
Rw (3.0 sin 60°) = mg (1.5 cos 60°)
Rw = mg / (2 tan 60°)
Rw = (10 kg) (9.8 m/s²) / (2√3)
Rw = 28 N
(b) State the friction at the foot of the ladder.
Take the sum of the forces in the x direction.
∑F = ma
Ff − Rw = 0
Ff = Rw
Ff = 28 N
(c) State the reaction at the foot of the ladder.
Take the sum of the forces in the y direction.
∑F = ma
Rf − mg = 0
Rf = mg
Rf = 98 N
As the speed increases and the pressure decreases
Answer:
88.5miles
Explanation:
the formula used to get the horizontal distance is R= (u^2sin2∆)÷g.
Answer:
The specific heat capacity of iridium = 0.130 J/g°C
Explanation:
Assuming no heat losses to the environment and to the calorimeter,
Heat lost by the iridium sample = Heat gained by water
Heat lost by the iridium sample = mC ΔT
m = mass of iridium = 23.9 g
C = specific heat capacity of the iridium = ?
ΔT = change in temperature of the iridium = 89.7 - 22.6 = 67.1°C
Heat lost by the iridium sample = (23.9)(C)(67.1) = (1603.69 C) J
Heat gained by water = mC ΔT
m = mass of water = 20.0 g
C = 4.18 J/g°C
ΔT = 22.6 - 20.1 = 2.5°C
Heat gained by water = 20 × 4.18 × 2.5 = 209 J
Heat lost by the iridium sample = Heat gained by water
1603.69C = 209
C = (209/1603.69) = 0.130 J/g°C
Answer:
No it can not
Explanation: Kinetic energy is the energy of motion so it can not be negative the kinetic energy can only be at a point of "0" which is when its not moving. (I hope this helped) :))
