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a_sh-v [17]
3 years ago
15

What kind of data does doppler radio provide

Physics
1 answer:
grin007 [14]3 years ago
6 0

Answer:

d

Explanation:

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The coefficient of cubical expansion of a substance depends upon
zzz [600]
<span>I think that the coefficient of cubical expansion of a substance depends on THE CHANGE IN VOLUME.

Cubical expansion, also known as, volumetric expansion has the following formula:

</span>Δ V = β V₁ ΔT

V₁ = initial volume of the body
ΔT = change in temperature of the body
β = coefficient of volumetric expansion.

β is defined as the <span>increase in volume per unit original volume per Kelvin rise in temperature.
</span>
With the above definition, it is safe to assume that the <span>coefficient of cubical expansion of a substance depends on the change in volume, which also changes in response to the change in temperature. </span>
7 0
3 years ago
What are challenges of securing a crime scene
kotegsom [21]

At any crime scene, the two greatest challenges to the physical evidence are contamination and loss of continuity.

<h3>What is the meaning of physical evidence?</h3>

In evidence law, physical evidence (also called real evidence or material evidence) is any material object that plays some role in the matter that gave rise to the litigation, introduced as evidence in a judicial proceeding (such as a trial) to prove a fact in issue based on the object's physical characteristics.

The two types of evidence at crime scenes:

Biological evidence (e.g., blood, body fluids, hair and other tissues)

Latent print evidence (e.g., fingerprints, palm prints, footprints)

The biggest impediment to an investigation is the removal or loss of a piece of evidence from the scene of a crime.

Hence, at any crime scene, the two greatest challenges to the physical evidence are contamination and loss of continuity.

Learn more about the physical evidence here:

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7 0
2 years ago
A magic medallion is suspended from a string inside a compartment of Hogwarts Express which is running straight westwards on hor
Serggg [28]

Answer:

a = 1 m/s²  and

Explanation:

The first two parts can be seen in attachment

We use Newton's second law on each axis

Y axis

      Ty - W = 0        

      Ty = w

X axis

     Tx = m a

With trigonometry we find the components of tension

    Sin θ = Ty / T

    Ty = T sin θ

    Cos θ = Tx / T

    Tx = T cos θ

We calculate the acceleration with kinematics

   Vf = Vo + a t

   a = (Vf -Vo) / t

   a = (20 -10) / 10

   a = 1 m/s²

We substitute in Newton's equations

     

  T Sin θ = mg

  T cos θ = ma

We divide the two equations

  Tan θ = g / a

  θ = tan⁻¹ (g / a)

  θ = tan⁻¹ (9.8 / 1)

  θ = 84º

We see that in the expression of the angle the mass does not appear therefore you should not change the angle

4 0
2 years ago
How to find resultant force?​
lys-0071 [83]

Assuming you're working in a 3D cartesian coordinate system, i.e. each point in space has an x, y, and z coordinate, you add up the forces' x/y/z components to find the resultant force.

8 0
3 years ago
20. A mass of gas has a volume of 4 m3, a temperature of 290 K, and an absolute pressure of 475 kPa. When the gas is allowed to
aliina [53]
Given:\\V_1=4m^3\\T_1=290K\\p_1=475kPa\\\\V_2=6.5m^3\\T_2=277K\\\\Find:\\p_2=?\\\\Solution:\\\\ \frac{pV}{T} =const.\\\\ \frac{p_1V_1}{T_1} = \frac{p_2V_2}{T_2} \\\\\frac{p_1V_1T_2}{T_1}=p_2V_2\\\\\frac{p_1V_1T_2}{T_1V_2}=p_2\\\\p_2=p_1 \frac{V_1}{V_2}  \frac{T_2}{T_1} \\\\\\p_2=475kPa\cdot  \frac{4m^3}{6.5m^3} \cdot  \frac{277K}{290K} \approx 279.2kPa\\\\Correct\;is\;answer\;\;C
7 0
2 years ago
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