The specific heat of the metal is 2.4733 J/g°C.
Given the following data:
- Initial temperature of water = 25.0°C
- Final temperature of water = 29.0°C
- Temperature of metal = 203.0°C
We know that the specific heat capacity of water is 4.184 J/g°C.
To find the specific heat of the metal (J/g°C):
Heat lost by metal = Heat gained by water.

Mathematically, heat capacity or quantity of heat is given by the formula;

<u>Where:</u>
- Q is the heat capacity or quantity of heat.
- m is the mass of an object.
- c represents the specific heat capacity.
- ∅ represents the change in temperature.
Substituting the values into the formula, we have:

Specific heat capacity of metal, c = 2.4733 J/g°C
Therefore, the specific heat of the metal is 2.4733 J/g°C.
Read more: brainly.com/question/18691577
Answer:
non-polar covalent bonds
this is when the electronegativity difference between the two non-metal atoms is very little to cause a partial charge (delta positive and delta negative; δ+ and δ-) on the atoms
Answer:
Not exactly But you can take the slope of the curved portion and the slope of the flatline.
It wont do you much good since your working for absorbance but if you ever see something like a temperature change you can use the slope(s) to find freezing points/melting
Explanation:
If you need to submit a slope you could use a best fit which is just point to point or you could break it up like i mentioned
Answer:
Nitrogen is limiting reactant while hydrogen is in excess.
Explanation:
Given data:
Mass of N₂ = 25 g
Mass of H₂ = 25 g
Mass of ammonia formed = ?
Solution:
Chemical equation:
N₂ + 3H₂ → 2NH₃
Number of moles of Nitrogen:
Number of moles = mass/ molar mass
Number of moles = 25 g/ 28 g/mol
Number of moles = 0.89 mol
Number of moles of hydrogen:
Number of moles = mass/ molar mass
Number of moles = 25 g/ 2 g/mol
Number of moles = 12.5 mol
Now we will compare the moles of both reactant with ammonia.
H₂ ; NH₃
3 : 2
12.5 : 2/3×12.5 = 8.3
N₂ ; NH₃
1 : 2
0.89 : 2×0.89 = 1.78
The number of moles of ammonia produced by nitrogen are less thus nitrogen is limiting reactant while hydrogen is in excess.