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saw5 [17]
3 years ago
6

Parallelogram PQRS is shown below. Parallelogram P Q R S. Angle P is 116 degrees. Angle R is opposite to angle P. What are the m

easures of the three remaining angles? Measure of angle Q = 116 degrees, Measure of angle R = 64 degrees, Measure of angle S = 64 degrees Measure of angle Q = 116 degrees, Measure of angle R = 116 degrees, Measure of angle S = 116 degrees Measure of angle Q = 64 degrees, Measure of angle R = 64 degrees, Measure of angle S = 64 degrees Measure of angle Q = 64 degrees, Measure of angle R = 116 degrees, Measure of angle S = 64 degrees
Chemistry
1 answer:
aliya0001 [1]3 years ago
5 0

Answer:

64 degrees

Explanation:

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A 30.0-g piece of metal at 203oC is dropped into 400.0 g of water at 25.0 oC. The water temperature rises to 29.0 oC. Calculate
oee [108]

The specific heat of the metal is 2.4733 J/g°C.

Given the following data:

  • Initial temperature of water = 25.0°C
  • Final temperature of water = 29.0°C
  • Mass of water = 400.0 g
  • Mass of metal = 30.0 g
  • Temperature of metal = 203.0°C

We know that the specific heat capacity of water is 4.184 J/g°C.

To find the specific heat of the metal (J/g°C):

Heat lost by metal = Heat gained by water.

Q_{metal} = Q_{water}

Mathematically, heat capacity or quantity of heat is given by the formula;

Q = mc\theta

<u>Where:</u>

  • Q is the heat capacity or quantity of heat.
  • m is the mass of an object.
  • c represents the specific heat capacity.
  • ∅ represents the change in temperature.

Substituting the values into the formula, we have:

30(203)c = 400(4.184)(29 \; -\; 20)\\\\6090c = 1673.6(9)\\\\6090c = 15062.4\\\\c = \frac{15062.4}{6090}

Specific heat capacity of metal, c = 2.4733 J/g°C

Therefore, the specific heat of the metal is 2.4733 J/g°C.

Read more: brainly.com/question/18691577

8 0
1 year ago
You used a variety of media with a NaCl concentration ranging from 0.5% to 15%. Which of these media would have the lowest water
Studentka2010 [4]

Answer:

Explanation:

B

7 0
2 years ago
7. Ionic bonds are at one end of the bond spectrum. What kinds of bonds are at the other end?
blondinia [14]

Answer:

non-polar covalent bonds

this is when the electronegativity difference between the two non-metal atoms is very little to cause a partial charge (delta positive and delta negative; δ+ and δ-) on the atoms

4 0
2 years ago
How do I find the slope of this graph?​ Is it even possible?
nasty-shy [4]

Answer:

Not exactly But you can take the slope of the curved portion and the slope of the flatline.

It wont do you much good since your working for absorbance but if you ever see something like a temperature change you can use the slope(s) to find freezing points/melting

Explanation:

If you need to submit a slope you could use a best fit which is just point to point or you could break it up like i mentioned

4 0
2 years ago
Identify limiting and excess reagents when 25g of nitrogen reacts with 25g of hydrogen. How many grams of ammonia gas are formed
Makovka662 [10]

Answer:

Nitrogen is limiting reactant while hydrogen is in excess.

Explanation:

Given data:

Mass of N₂ = 25 g

Mass of H₂ = 25 g

Mass of ammonia formed = ?

Solution:

Chemical equation:

N₂ + 3H₂    →     2NH₃

Number of moles of Nitrogen:

Number of moles = mass/ molar mass

Number of moles = 25 g/ 28 g/mol

Number of moles = 0.89 mol

Number of moles of hydrogen:

Number of moles = mass/ molar mass

Number of moles = 25 g/ 2 g/mol

Number of moles = 12.5 mol        

Now we will compare the moles of both reactant with ammonia.

                   H₂            ;             NH₃

                    3             :              2

                    12.5        :            2/3×12.5 = 8.3

                 

                   N₂            ;             NH₃

                    1              :              2

                    0.89        :            2×0.89 = 1.78

The number of moles of ammonia produced by nitrogen are less thus nitrogen is limiting reactant while hydrogen is in excess.

7 0
3 years ago
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