All categories

3 years ago

The vapor pressure of pure acetone (C3H6O) is 216 torr

Chemistry

1 answer:

svetoff [14.1K]3 years ago

6 0

The mole fraction of acetone (C₃H₆O) is 0.333

<h3>Data obtained from the question </h3>

Mole of C₃H₆O = 0.1 mole
Mole of CHCl₃ = 0.2 mole
Mole fraction of C₃H₆O =?

<h3>How to determine the mole fraction </h3>

Mole fraction of a substance can be obtained by using the following formula:

Mole fraction = mole / total mole

With the above formula, we can obtain the mole fraction of C₃H₆O as follow:

Mole of C₃H₆O = 0.1 mole
Mole of CHCl₃ = 0.2 mole
Total mole = 0.1 + 0.2 = 0.3 mole
Mole fraction of C₃H₆O =?

Mole fraction = mole / total mole

Mole fraction of C₃H₆O = 0.1 / 0.3

Mole fraction of C₃H₆O = 0.333

Learn more about mole fraction:

brainly.com/question/2769009

You might be interested in

What does it mean if the plus sign is positive for the sodium atom?

solniwko [45]

The charge of the ion is +1

5 0

3 years ago

How would you prepare 250 mL of a 0.100 M solution of fluoride ions<br> from solid CaF2?

andrey2020 [161]

In 250 mL of volumetric flask add 0.975875 grams of $CaF_2$ and dissolve it in the 250 mL of water.

Given:

The solid of calcium fluoride.

To prepare:

The 250 mL solution of 0.100 M of fluoride ions from solid calcium fluoride.

Method:

Molarity of the fluoride ion solution needed = M = 0.100 M

The volume of the fluoride ion solution needed = V = 250 mL

$1 mL = 0.001L\\V=250 mL=250\times 0.001 L=0.250 L$

The moles of fluoride ion needed = n

According to the definition of molarity:

$M=\frac{n}{V}\\0.100M=\frac{n}{0.250 L}\\n=0.100M\times 0.250 L=0.025 mol$

Moles of fluoride ion = 0.025 mol

We know that solid calcium fluoride dissolves in water to give calcium ions and fluoride ions.

$CaF_2(s)\rightarrow Ca^{2+}(aq)+2F^-(aq)$

According to reaction, 2 moles of fluoride ions are obtained from 1 mole of calcium fluoride, then 0.025 moles of fluoride ions will be obtained from:

$=\frac{1}{2}\times 0.025 mol=0.0125 \text{mol of } CaF_2$

Moles of calcium fluoride = 0.0125 mol

Mass of calcium fluoride needed to prepare the solution :

$=0.0125 mol\times 78.07 g/mol=0.975875 g$

Preparation:

Weight 0.975875 grams of calcium fluoride
Add weighed calcium fluoride to a volumetric flask of the labeled volume of 250 mL.
Now add a small amount of water to dissolve the calcium fluoride completely.
After this add more water up to the mark of the volumetric flask of volume 250 mL.

Learn more about molarity of solution ere:

brainly.com/question/10053901?referrer=searchResults

brainly.com/question/10270173?referrer=searchResults

3 0

3 years ago

Select the correct answer. An adult human lung has a volume of 2. 9 liters. If its volume decreases to 1. 2 liters and it contai

maria [59]

Moles are the ratio of the mass and the molar mass of the substance given and is estimated in mol. The moles that the lungs contain when it is full is 0.12 moles.

<h3>What is the relation of the volume and moles?</h3>

Moles of the substances are directly proportional to the volume of the substance and can be shown as,

$\rm \dfrac{V_{1}}{V_{2}}= \dfrac{n_{1}}{n_{2}}$