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tensa zangetsu [6.8K]

4 years ago

15

How does the vertical component of a projectile’s motion compare with the motion of vertical free fall when air resistance is ne

gligible?
1. Identical to that of free fall
2. Greater than that of free fall
3. It cannot be determined.
4. Less than that of free fall

1 answer:

exis [7]4 years ago

8 0

Answer:

1. Identical to that of free fall

Explanation:

As we know that there is same external force acting on an object when it is released in the air which is given as

$F = mg$

so here in vertical direction the acceleration is given as

$a = \frac{F_y}{m}$

so we will have

$a = \frac{mg}{m}$

$a_y = g$

so we can say that in vertical direction the acceleration is always same while object is in vertical motion or it is in projectile motion

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The radioactive element polonium decays according to the law given below where Q0 is the initial amount and the time t is measur

kogti [31]

Answer:

1280 mg

Explanation:

Radioactive decay is a phenomenon that occurs when a certain isotope of an element, said to be radioactive, decays, turning into a lighter nucleus and emitting radiation + energy in the process.

The radioactive decay of this isotope of polonium is described by the equation

$Q(t)=Q_0 2^{-\frac{t}{140}}$

where

$Q(t)$ is the amount of polonium left after time t

$Q_0$ is the amount of polonium t time t = 0

$140$ is the half-life of the polonium, in days (it is the time it takes for the initial element to halve its amount)

IN this problem, we know that:

After t = 560 days, the amount of polonium left is $Q(t)=80 mg$ . Therefore, we can re-arrange the equation, substituting t = 560 d, and solve for $Q_0$ to find the initial amount of polonium:

$Q_0 = Q(t) \cdot 2^{\frac{t}{140}}=(80)\cdot 2^{\frac{560}{140}}=1280 mg$

5 0

4 years ago

Please help I’ll give brainliest

In-s [12.5K]

Answer:

2nd option

Explanation:

Static electricity the charges are at rest and they are accumulating on the surface of the insulator.

Current electricity the electrons are moving inside the conductor.

4 0

3 years ago

Which of the following represents a concave lens?<br> A. -di<br> B. +di<br> C. -f<br> D. +f

Nina [5.8K]

Answer:

The answer is option D. +f

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3 years ago

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The eye of a hurricane passes over grand bahama island in a direction 60.0Â° north of west with a speed of 41.0 km/h. three hour

Ksivusya [100]

initial velocity is given as 41 km/h at 60 degree North of West

$v_i = -41 cos60\hat i + 41 sin60 \hat j$

$v_i = -20.5 \hat i + 35.5 \hat j$

After some time the velocity is given as

$v_f = 25 \hat j$

now we can find the acceleration

$a = \frac{v_f - v_i}{t}$

$a = \frac{25\hat j - (-20.5 \hat i + 35.5 \hat j)}{3}$

$a = 6.83 \hat i - 3.5 \hat j$

now the distance is given by

$d = v*t + \frac{1}{2} at^2$

$d = (-20.5 \hat i + 35.5 \hat j)*4.5 + 0.5*(6.83 \hat i - 1.5 \hat j)* 4.5^2$

$d = -92.25\hat i + 159.75\hat j + 69.15\hat i - 15.19\hat j$

$d = -23.1 \hat i + 144.56\hat j$

so the magnitude of distance is

$d = \sqrt{23.1^2 + 144.56^2} = 146.4 km$

8 0

3 years ago

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A 25.2 kg gazelle moving 2.33 m/s

docker41 [41]

Force = mass x acceleration
113N = 25.2a
a = 4.48 m/s^2
Vf = Vi + at
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3 years ago