Question

If 7.0 mol sample of a gas has a volume of 12.2 L, what would the volume be if the amount of gas was increased to 16.8 mol

Answer 1

Answer:

$V_{2} = 29.28\,L$

Explanation:

Let assume that gas behaves ideally and experiments an isobaric and isothermal processes. The following relationship is applied to determined the final volume:

$\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}$

$V_{2} = V_{1} \cdot \left(\frac{n_{2}}{n_{1}} \right)$

$V_{2} = (12.2\,L)\cdot \left(\frac{16.8\,moles}{7\,moles} \right)$

$V_{2} = 29.28\,L$