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Pachacha [2.7K]
3 years ago
7

What is chemical and physical properties? !

Chemistry
2 answers:
Scilla [17]3 years ago
7 0

Answer:

Physical property: Any characteristic that can be determined without changing the substance's chemical identity. Chemical property: Any characteristic that can be determined only by changing a substance's molecular structure.

Explanation:

Physical properties are something that is reverseable or has no change visible. Chemical properties are something that is NOT reverseable.

Chemical: Gas forming or Color Changing. (ETC.)

luda_lava [24]3 years ago
7 0

Answer:

physical property means any characteristic that can be determined without changing the substance's chemical identity. chemical property is any characteristic that can be determined only by changing a substance's molecular structure.

out of my textbook hope it helps

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Rainbow [258]

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7 0
2 years ago
What is the new volume of a balloon originally at 755 torr and 5.00 l is placed in a container in which the pressure is increase
Luba_88 [7]

Answer is: volume will be 3.97 liters.

Boyle's Law: the pressure volume law -  volume of a given amount of gas held  varies inversely with the applied pressure when the temperature and mass are constant.

p₁V₁ = p₂V₂.

p₁ = 755 torr.

V₁ = 5.00 l.

p₂ = 1.25 atm · 760 torr/atm.

p₂ = 950 torr.

755 torr · 5 l = 950 torr · V₂.

V₂ = 755 torr · 5 l / 950 torr.

V₂ =  3.97 l.

When pressure goes up, volume goes down.

When volume goes up, pressure goes down.

3 0
3 years ago
Read 2 more answers
Two systems with heat capacities 19.9 J mol-1 K-1 and 28.2 ] mol 1 K-1 respectively interact thermally and come to an equilibriu
MAVERICK [17]

Answer : The initial temperature of system 2 is, 19.415^oC

Explanation :

In this problem we assumed that the total energy of the combined systems remains constant.

-q_1=q_2

m\times c_1\times (T_f-T_1)=-m\times c_2\times (T_f-T_2)

The mass remains same.

where,

C_1 = heat capacity of system 1 = 19.9 J/mole.K

C_2 = heat capacity of system 2 = 28.2 J/mole.K

T_f = final temperature of system = 30^oC=273+30=303K

T_1 = initial temperature of system 1 = 45^oC=273+45=318K

T_2 = initial temperature of system 2 = ?

Now put all the given values in the above formula, we get

-19.9J/mole.K\times (303-318)K=28.2J/mole.K\times (303-T_2)K

T_2=292.415K

T_2=292.415-273=19.415^oC

Therefore, the initial temperature of system 2 is, 19.415^oC

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3 years ago
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