The ion hydroxide is common to all alkalis.
Answer:
a. NaHCO₃ + HCl → NaCl + H₂O + CO₂
b. 39.14 g is the mass of NaHCO₃ required to produce 20.5 moles of CO₂
Explanation:
A possible reaction for NaHCO₃ to make dioxide is this one, when it reacts with hydrochloric to produce the mentioned gas.
NaHCO₃ + HCl → NaCl + H₂O + CO₂
Ratio in this reaction is 1:1
So 1 mol of baking soda, produce 1 mol of CO₂
Let's calculate the moles
20.5 g CO₂ / 44 g/m = 0.466 moles
This moles of gas came from the same moles of salt.
Molar mass baking soda = 84 g/m
Molar mass . moles = mass
84 g/m . 0.466 moles = 39.14 g
Answer:
Explanation:
in a combustion of ethane 2 moles of ethane react with 7 moles of O2
now no of moles in 54 gram of O2=mass/ molar mass
moles =54/32=1.7 moles
if 7 moles of O2 required 2 moles of ethane then 1.7 mole required=?
7 moles of O2=2 moles of C2H6
1.7 moles of O2=1.7*2/7=0.5 moles of C2H6
0.5 moles of C2H6 contain how much grams=?
mass= moles*molar mass=0.5*30=15
Answer:
NH4NO3 is the answer
Explanation:
Please mark as brainliest
Answer:
1 and 2
Explanation:
When Concentrated H2SO4 reacted with the alcohols, they produce cycloalkenes. This is a mechanism known as dehydration of alcohols with an acid catalyst. This is because concentrated H2SO4 acts as a great oxidizing agent. In the process, the alcohols are heated to a high temperature with an excess of pure sulfuric acid. By passing the gases through a sodium hydroxide solution, the carbon dioxide and sulfur dioxide produced by reactive species are eliminated. The reaction mechanism shown in the image below indicates that only compounds 1 and 2 produce only one product.
