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-Dominant- [34]
2 years ago
15

How does your body get the energy that it needs to do all of its daily activities? Describe the energy conversion that take plac

e.
Chemistry
1 answer:
Mama L [17]2 years ago
8 0
IF you are fat like your mom well i don't know
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Why is it important for scientists to review and repeat the work of other scientists
guapka [62]

Answer:

Accuracy

Explanation:

It is important for scientists to review the work of other scientists, so they can be sure there are no mistakes or lack of judgement. They repeat to compare results to make hypotheses.

3 0
2 years ago
A student dissolves equal amounts of salt in equal amounts of warm water, room-temperature water, and ice water. Which result is
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doesnt salt desolve ice? so wouldn't the salt dissolve in the ice water?

6 0
3 years ago
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Hi, how are you today i want you to answer this question please because it’s homework for my sister and she have to show the tea
vfiekz [6]

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The Earth's surface is constantly changing through forces in nature. The daily processes of precipitation, wind and land movement result in changes to landforms over a long period of time. Driving forces include erosion, volcanoes and earthquakes. People also contribute to changes in the appearance of land.

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2 years ago
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A certain reaction with an activation energy of 185 kJ/mol was run at 505 K and again at 525 K . What is the ratio of f at the h
frosja888 [35]

Answer:

The ratio of f at the higher temperature to f at the lower temperature is 5.356

Explanation:

Given;

activation energy, Ea = 185 kJ/mol = 185,000 J/mol

final temperature, T₂ = 525 K

initial temperature, T₁ = 505 k

Apply Arrhenius equation;

Log(\frac{f_2}{f_1} ) = \frac{E_a}{2.303 \times R} [\frac{1}{T_1} -\frac{1}{T_2} ]

Where;

\frac{f_2}{f_1}  is the ratio of f at the higher temperature to f at the lower temperature

R is gas constant = 8.314 J/mole.K

Log(\frac{f_2}{f_1} ) = \frac{E_a}{2.303 \times R} [\frac{1}{T_1} -\frac{1}{T_2} ]\\\\Log(\frac{f_2}{f_1} ) = \frac{185,000}{2.303 \times 8.314} [\frac{1}{505} -\frac{1}{525} ]\\\\Log(\frac{f_2}{f_1} ) = 0.7289\\\\\frac{f_2}{f_1}  = 10^{0.7289}\\\\\frac{f_2}{f_1}  = 5.356

Therefore, the ratio of f at the higher temperature to f at the lower temperature is 5.356

5 0
3 years ago
The incomplete table below shows selected characteristics of gas laws.
lorasvet [3.4K]

Answer:

pressure and temperature

Explanation:

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