Answer:
sometimes
Step-by-step explanation:
If the polygon is regular that is the length of each side of the polygon is equal and each angle is equal in that case only interior angles are equal .
For a polygon even if a side length is different or interior angle is different then its a irregular polygon and then in that case each interior angle cannot be termed as equal.
Thus, we know that that there are two type of polygon regular and irregular.
Thus, it can be said that it is not necessary that Each of the interior angles in a polygon are equal always
Also it can be said that it is not necessary that Each of the interior angles in a polygon are never equal (as regular polygon have equal angles)
Thus, we can only say that each of the interior angles in a polygon are sometimes equal .
Answer:
x = 10
Step-by-step explanation:
Answers:
- x = 7
- Area of shaded region = 162 square units
You may need to leave off the "square units" portion.
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Explanation:
For now, ignore the smaller rectangle and its dimensions. The larger rectangle has sides 3x and x+5, which I'll call the length and width.
L = 3x
W = x+5
The perimeter of any rectangle is P = 2(L+W). Plug in those values of L and W, and also the given perimeter P = 66. Isolate x.
P = 2(L+W)
2(L+W) = P
2(3x+x+5) = 66
2(4x+5) = 66
8x+10 = 66
8x = 66-10
8x = 56
x = 56/8
x = 7
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Now that we know x, we can find the area of the rectangles.
As you probably can guess, the shaded region is the difference of the two areas.
A = area of larger rectangle
A = (length)*(width)
A = (3x)*(x+5)
A = (3*7)*(7+5)
A = 252
B = area of smaller rectangle
B = (x+3)*(x+2)
B = (7+3)*(7+2)
B = 90
C = area of shaded region
C = A - B
C = 252 - 90
C = 162 square units is the area of the shaded region.
Whenever you multiply a binomial by itself twice, the resulting trinomial is called a perfect square trinomial
For example, (x + 1) × (x + 1) = x2<span> + x + x + 1 = x</span>2<span> + 2x + 1 and x</span>2<span> + 2x + 1 is a perfect square trinomial</span>
Another example is (x − 5) × (x − 5)
(x − 5) × (x − 5) = x2<span> + -5x + -5x + 25 = x</span>2<span> + -10x + 25 and x</span>2<span> + -10x + 25 is a perfect square trinomial </span>
Now, we are ready to start factoring perfect square trinomials
The model to remember when factoring perfect square trinomials is the following:
a2<span> + 2ab + b</span>2<span> = (a + b)</span>2<span> and (a + b)</span>2<span> is the factorization form for a</span>2<span> + 2ab + b</span>2
Notice that all you have to do is to use the base of the first term and the last term
In the model just described,
the first term is a2<span> and the base is a</span>
the last term is b2<span> and the base is b</span>
Put the bases inside parentheses with a plus between them (a + b)
Raise everything to the second power (a + b)2<span> and you are done </span>
<span>Notice that I put a plus between a and b. </span>You will put a minus if the second term is negative!
a2<span> + -2ab + b</span>2<span> = (a − b)</span>2
Remember that a2<span> − 2ab + b</span>2<span> = a</span>2<span> + -2ab + b</span>2<span> because a minus is the same thing as adding the negative ( − = + -) So, a</span>2<span> − 2ab + b</span>2<span> is also equal to (a − b)</span>2
Example #1:
Factor x2<span> + 2x + 1</span>
Notice that x2<span> + 2x + 1 = x</span>2<span> + 2x + 1</span>2
Using x2<span> + 2x + 1</span>2, we see that... the first term is x2<span> and the base is x</span>
the last term is 12<span> and the base is 1</span>
Put the bases inside parentheses with a plus between them (x + 1)
Raise everything to the second power (x + 1)2<span> and you are done </span>
Example #2:
Factor x2<span> + 24x + 144</span>
But wait before we continue, we need to establish something important when factoring perfect square trinomials.
<span>. How do we know when a trinomial is a perfect square trinomial? </span>
This is important to check this because if it is not, we cannot use the model described above
Think of checking this as part of the process when factoring perfect square trinomials
We will use example #2 to show you how to check this
Start the same way you started example #1:
Notice that x2<span> + 24x + 144 = x</span>2<span> + 24x + 12</span>2
Using x2<span> + 24x + 12</span>2, we see that...
the first term is x2<span> and the base is x</span>
the last term is 122<span> and the base is 12</span>
Now, this is how you check if x2<span> + 24x + 12</span>2<span> is a perfect square</span>
If 2 times (base of first term) times (base of last term) = second term, the trinomial is a perfect square
If the second term is negative, check using the following instead
-2 times (base of first term) times (base of last term) = second term
Since the second term is 24x and 2 × x × 12 = 24x, x2<span> + 24x + 12</span>2<span> is perfect and we factor like this</span>
Put the bases inside parentheses with a plus between them (x + 12)
Raise everything to the second power (x + 12)2<span> and you are done </span>
Example #3:
Factor p2<span> + -18p + 81</span>
Notice that p2<span> + -18p + 81 = p</span>2<span> + -18p + 9</span>2
Using p2<span> + -18p + 9</span>2, we see that...
the first term is p2<span> and the base is p</span>
the last term is 92<span> and the base is 9</span>
Since the second term is -18p and -2 × p × 9 = -18p, p2<span> + -18p + 9</span>2<span> is a perfect square and we factor like this</span>
Put the bases inside parentheses with a minus between them (p − 9)
Raise everything to the second power (p − 9)2<span> and you are done </span>
Example #4:
Factor 4y2<span> + 48y + 144</span>
Notice that 4y2<span> + 48y + 144 = (2y)</span>2<span> + 48y + 12</span>2
(2y)2<span> + 48y + 12</span>2, we see that...
the first term is (2y)2<span> and the base is 2y</span>
the last term is 122<span> and the base is 12</span>
Since the second term is 48y and 2 × 2y × 12 = 48y, (2y)2<span> + 48p + 12</span>2<span> is a perfect square and we factor like this</span>
Put the bases inside parentheses with a plus between them (2y + 12)
Raise everything to the second power (2y + 12)2<span> and you are done </span>
Answer:
B
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = 3x - 1 ← is in slope- intercept form
with slope m = 3
Parallel lines have equal slopes, thus
y = 3x + c ← is the partial equation of the parallel line
To find c substitute (2, 2) into the partial equation
2 = 6 + c ⇒ c = 2 - 6 = - 4
y = 3x - 4 → B