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Sveta_85 [38]
3 years ago
15

A 47.5-turn circular coil of radius 5.25 cm can be oriented in any direction in a uniform magnetic field having a magnitude of 0

.535 T. If the coil carries a current of 26.9 mA, find the magnitude of the maximum possible torque exerted on the coil.
Physics
1 answer:
Free_Kalibri [48]3 years ago
3 0

Answer:

Torque, 5.91\times 10^{-3}\ N-m

Explanation:

Given that,

The number of turns in the coil, N = 47.5

Radius of the coil, r = 5.25 cm

Uniform magnetic field, B = 0.535 T

Current in the coil, I = 26.9 mA

The magnitude of the maximum possible torque exerted on the coil isg given by :

\tau=NIAB\\\\\tau=47.5\times 26.9\times 10^{-3}\times \pi (5.25\times 10^{-2})^2\times 0.535 \\\\\tau=0.00591\ N-m\\\\\tau=5.91\times 10^{-3}\ N-m

So, the magnitude of the maximum possible torque exerted on the coil is 5.91\times 10^{-3}\ N-m.

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An unpolarized light with an intensity of 20W/m^2 is passed through a pair of polarizers. The first polarizer is set at an angle
bogdanovich [222]

Answer:

4.416 W/m²

Explanation:

Malus' law is given mathematically as

I = I₀ cos² θ

For the first polarizer, θ = 60°

I₁ = I₀ cos² 60°

I₁ = I₀ (0.5)² = 0.25I₀

For the second polarizer, θ = 20°

I₂ = I₁ cos² 20°

I₂ = I₁ (0.9397)² = 0.883 I₁

I₂ = 0.883 × 0.25I₀ = 0.2208 I₀

Note that

I₀ = 20 W/m²

I₂ = 0.2208 × 20 = 4.416 W/m²

Hope this Helps!!!

6 0
3 years ago
3. Two cyclists that are 500 m apart start biking toward each other. They bike at speeds of 6 and
Veronika [31]

Answer:

A) 50 seconds

B) 200 m

Explanation:

They are 500 metres apart.

And one of the bike loves at 6 m/s while the other loves at 4 m/s.

A) Let distance of the 6 m/s bike before they meet be x.

Thus, time = x/6

Since time = distance/speed

For the second bike at 4 m/s, his distance covered before they meet will be 500 - x

Thus, time = (500 - x)/4

Now they will meet each other at the same time. Thus;

x/6 = (500 - x)/4

Cross multiply to get;

4x = 3000 - 6x

6x + 4x = 3000

10x = 3000

x = 3000/10

x = 300 m

Thus, time will be;

t = 300/6

t = 50 seconds

B) Distance covered by the slower bike is (500 - x)

Since from a above, x = 300

Thus; distance = 500 - 300 = 200 m

4 0
3 years ago
Consider two diffraction gratings with the same slit separation. The only difference between the two gratings is that one gratin
kobusy [5.1K]

Answer:

True The grid with more slits gives more angle separation increases

True. The grating with 10 slits produces better-defined (narrower) peaks

Explanation:

Such a system can be seen as a diffraction network in this case with different number of lines per unit length, the expression for the constructive interference of a diffraction network is

      d sin θ = m λ

where d is the distance between slits or lines, m the order of diffraction and λ the wavelength.

For network with 5 slits

      d = 1/5 = 0.2

For the network with 10 slits

      d = 1/10 = 0.1

let's calculate the separation (teat) for each one

      θ = sin⁻¹ (m λ / d)

for 5 slits

     θ₅ = sin⁻¹ (m λ 5)

for 10 slits

     θ₁₀ = sin⁻¹ (m λ 10)

we can appreciate that for more slits the angle increases

the intensity of a series of slits is

       I = I₀ sin²2 (N d/2) / sin² d/2)

when there are more slits (N) the peaks have greater intensity and are more acute (half width decreases)

let's analyze the claims

False

True The grid with more slits gives more angle separation increases

False

True The expression for the intensity of the diffraction peaks the intensity of the peaks increases with the number of slits as well as their spectral width decreases

False

5 0
4 years ago
Which is an example of nuclear energy being converted into heat and light energy?
likoan [24]
The answer to the question is A 
6 0
3 years ago
Read 2 more answers
After your school's team wins the regional championship, students go to the dorm roof and start setting off fireworks rockets. T
PIT_PIT [208]

Answer:

160 m

Explanation:

The intensity, I, of the sound is inversely proportional to the square of the distance, r, from the source.

I\propto \dfrac{1}{r^2}

Hence,

I_1r_1^2 = I_2r_2^2

r_2 = r_1\sqrt{\dfrac{I_1}{I_2}}

From the question, I_2 is half of I_1

r_2 = r_1\sqrt{\dfrac{I_1}{0.5I_1}}

r_2 = r_1\sqrt{2}

r_2 = 113\text{ m}\sqrt{2} = 160 \text{ m}

3 0
3 years ago
Read 2 more answers
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