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vladimir1956 [14]
3 years ago
5

Compare and contrast the terms homologous and analogous.

Chemistry
1 answer:
I am Lyosha [343]3 years ago
5 0

Analogous structures are those structures in different species which perform the same function, have similar appearance and structure but are not evolved together; therefore do not share a common ancestor. Homologous and analogous organs video explains in a simple way.

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When would a life scientist study a nonliving thing such as a rock or lake
VladimirAG [237]
He would study it so he could see how it interacted with the living things around it.

3 0
3 years ago
Pb(NO3)2 + K2CO3 --&gt; PbCO3 + KNO3<br> A. 5<br> B. 2<br> C.<br> 4
emmasim [6.3K]

Answer:

Pb(NO3)2 + K2CO3 ----> PbCO3 + 2KNO3

The answer is B. 2

Hope this helps!

4 0
3 years ago
What are the two processes of ocean to cloud?
IceJOKER [234]

Answer: The excess amount changes from a gas into a liquid or solid (ice). The process of water changing from a gas to a liquid is called "condensation," and when gas changes directly into a solid, it is called "deposition." These two processes are how clouds form.

4 0
3 years ago
Question 4 (1 point)<br> If you have exactly one million atoms how many moles do you have?
rjkz [21]

Answer:

                       1.66 × 10⁻¹⁸  Moles

Explanation:

                     As we know one mole of any substance contains 6.022 × 10²³ particles (atoms, ions, molecules or formula units). This number is also called as Avogadro's Number.

The relation between Moles, Number of Atoms and Avogadro's Number is given as,

             Number of Moles  =  Number of Atoms ÷ 6.022 × 10²³ Atoms/mol

Putting values,

              Number of Moles  =  1.0 × 10⁶ Atoms ÷ 6.022 × 10²³ Atoms/mol

              Number of Moles  =  1.66 × 10⁻¹⁸  Moles

7 0
3 years ago
Suppose that 33.3 J of heat is added to an ideal gas. The gas expands at a constant pressure of 1.45 104 Pa while changing its v
levacccp [35]

Answer:

ΔU = 25.8 J

Explanation:

The gas absorbs 33.3 J of heat, that is, Q = 33.3 J.

The work (W) of expansion can be calculated using the following expression:

W = -P. ΔV

where,

P is the external pressure

ΔV is the change in volume

W = -1.45 × 10⁴ N . m⁻² × (8.40 × 10⁻⁴ m³ - 3.24 × 10⁻⁴ m³) = -7.48 J

The change in the internal energy (ΔU) is:

ΔU = Q + W

ΔU =  33.3 J + (-7.48 J) = 25.8 J

5 0
3 years ago
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