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3 years ago

Which of the following equations represent

Chemistry

1 answer:

Harrizon [31]3 years ago

5 0

Answer:

a. MgO(s) + H2CO3(aq) → MgCO3(s) + H2O(l) DOUBLE DISPLACEMENT REACTION.

b. 2KNO3(s)→2KNO2 (s) + O2(8) DESCOMPOSITION REACTION.

c. H2(g) + CuO(s) → Cu(s) + H2O(1) SINGLE DISPLACEMENT REACTION.

d. NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(1) COMBUSTION REACTION.

e. H2(8) + Cl2(g) → 2HCl(8) SYNTHESIS REACTION.

f. SO3(g) + H2O(1)→ H2SO4(aq) SYNTHESIS REACTION.

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How many moles of oxygen are in 2.00 moles of NaCIO4?

Klio2033 [76]

Answer: 8 Moles of Oxygen

Explanation: The formula shows that there are (exactly) 4 oxygen atoms in each mole or formula unit. Therefore 4 * 2.00 = 8.

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3 years ago

Compare urban and rural land .how are each used?

Ksivusya [100]

Answer:

"Urban area is used for the buildings, industries etc, whereas the rural areas are used for cultivation, forest cover etc."

Explanation:

When we talk about the urban land they are mostly covered with buildings, industries, roads and apartments and also the municipal structures. But when we talk about the rural land it has less dense population with forest cover, agricultural lands, rangeland and also different land cover type. In the urban areas the population density is very high. Those areas that located in the outskirt of the town are the rural areas.

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3 years ago

Identify bohrs model of the atom. His model described the reactivity of an element based on its number of valence electrons.

4vir4ik [10]

E is Bohrs model the dots on the rings represent the valence electrons

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3 years ago

Read 2 more answers

A metal sample weighing 129.00 grams and at a temperature of 97.8 degrees Celsius was placed in 45.00 grams of water in a calori

Nitella [24]

Answer : The specific heat of metal is $0.481J/g^oC$ .

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

$q_1=-q_2$

$m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)$

where,

$c_1$ = specific heat of metal = ?

$c_2$ = specific heat of water = $4.184J/g^oC$

$m_1$ = mass of metal = 129.00 g

$m_2$ = mass of water = 45.00 g

$T_f$ = final temperature = $39.6^oC$

$T_1$ = initial temperature of metal = $97.8^oC$

$T_2$ = initial temperature of water = $20.4^oC$

Now put all the given values in the above formula, we get

$129.00g\times c_1\times (39.6-97.8)^oC=-45.00g\times 4.184J/g^oC\times (39.6-20.4)^oC$

$c_1=0.481J/g^oC$

Therefore, the specific heat of metal is $0.481J/g^oC$ .

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3 years ago

AgNO2+Na3PO4<br><br> Solve and predict if its a precipitate

ASHA 777 [7]

To identify a precipitation reaction and predict solubilities. ... solution of potassium dichromate to give a reddish precipitate of ... When aqueous solutions of silver nitrate and potassium dichromate are ...
Missing: AgNO2+

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3 years ago