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svetlana [45]
3 years ago
5

Which of the following equations represent

Chemistry
1 answer:
Harrizon [31]3 years ago
5 0

Answer:

a. MgO(s) + H2CO3(aq) →  MgCO3(s) + H2O(l) DOUBLE DISPLACEMENT REACTION.

b. 2KNO3(s)→2KNO2 (s) + O2(8) DESCOMPOSITION REACTION.

c. H2(g) + CuO(s) → Cu(s) + H2O(1) SINGLE DISPLACEMENT REACTION.

d. NaOH(aq) + HCl(aq) →  NaCl(aq) + H2O(1) COMBUSTION  REACTION.

e. H2(8) + Cl2(g) → 2HCl(8) SYNTHESIS REACTION.

f. SO3(g) + H2O(1)→ H2SO4(aq) SYNTHESIS REACTION.

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The transuranium elements are produced by the capture of neutrons

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Write the formula for lead oxide.
serious [3.7K]

Answer:

<h2>Lead(II) oxide</h2>

Explanation:

<h3>Lead(II) oxide, also called lead monoxide, is the inorganic compound with the molecular formula PbO. PbO occurs in two polymorphs: litharge having a tetragonal crystal structure, and massicot having an orthorhombic crystal structure. Modern applications for PbO are mostly in lead-based industrial glass and industrial ceramics, including computer components. It is an amphoteric oxide.[3]</h3>

  • IUPAC name
  • Lead(II) oxide

  • Other names
  • Lead monoxide
  • Litharge
  • Massicot
  • Plumbous oxide
  • Galena

<h2> Preparation</h2><h3>PbO may be prepared by heating lead metal in air at approximately 600 °C (1,100 °F). At this temperature it is also the end product of oxidation of other oxides of lead in air:[4]</h3><h3>Thermal decomposition of lead(II) nitrate or lead(II) carbonate also results in the formation of PbO:</h3>

<h3>2 Pb(NO</h3><h3>3)</h3><h3>2 → 2 PbO + 4 NO</h3><h3>2 + O</h3><h3>2</h3><h3>PbCO</h3><h3>3 → PbO + CO2</h3><h3>PbO is produced on a large scale as an intermediate product in refining raw lead ores into metallic lead. The usual lead ore is galena (lead(II) sulfide). At a temperature of around 1,000 °C (1,800 °F) the sulfide is converted to the oxide:[5]</h3>

<h3>2 PbS + 3 O</h3><h3>2 → 2 PbO + 2 SO2</h3><h3>Metallic lead is obtained by reducing PbO with carbon monoxide at around 1,200 °C (2,200 °F):[6]</h3>

<h3>PbO + CO → Pb + CO2</h3>

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I am pretty sure the answer is C.

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