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svetlana [45]
3 years ago
5

Which of the following equations represent

Chemistry
1 answer:
Harrizon [31]3 years ago
5 0

Answer:

a. MgO(s) + H2CO3(aq) →  MgCO3(s) + H2O(l) DOUBLE DISPLACEMENT REACTION.

b. 2KNO3(s)→2KNO2 (s) + O2(8) DESCOMPOSITION REACTION.

c. H2(g) + CuO(s) → Cu(s) + H2O(1) SINGLE DISPLACEMENT REACTION.

d. NaOH(aq) + HCl(aq) →  NaCl(aq) + H2O(1) COMBUSTION  REACTION.

e. H2(8) + Cl2(g) → 2HCl(8) SYNTHESIS REACTION.

f. SO3(g) + H2O(1)→ H2SO4(aq) SYNTHESIS REACTION.

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Elodia [21]

Answer:

Fe + Cu(NO3)2 →

Explanation:

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3 years ago
How many grams of sodium sulfide can be produced when 45.3 g Na react with 105 g S?
RoseWind [281]
The chemical reaction would be as follows:

<span>2Na + S → Na2S

We are given the amount of the reactants to be used in the reaction. We use these to calculate the amount of product. We do as follows:

45.3 g Na ( 1 mol / 22.99 g ) = 1.97 mol Na
105 g S ( 1 mol / 32.06 g ) = 3.28 mol S

The limiting reactant would be Na. We calculate as follows:

1.97 mol Na ( 1 mol Na2S / 2 mol Na ) (78.04 g / mol ) = 76.87 g Na2S produced</span>
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2 years ago
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4 0
3 years ago
At a certain temperature, the ph of a neutral solution is 7.43. what is the value of kw at that temperature? express your answer
Delvig [45]

The formula for Kw is:

Kw= [H]*[OH]

where [H] and [OH] are concentrations 

We are given the pH so we can calculate the [H] concentration from the formula:
pH=-log[H] 
7.43 = -log[H]

[H] = 3.715x10^-8 M

In neutral solution, [H] = [OH], therefore: 

<span>[OH]= 3.715x10^-8 M

Calculating Kw:

Kw = (3.715x10^-8)*( 3.715x10^-8)</span>

<span>Kw = 1.38 x 10^-15 </span>

7 0
3 years ago
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