To the nearest tenth, what is the population density of bacteria at the end of the third hour in petri dish A?
1 answer:
Answer:
The question is not complete or missing details. Here is a similar question ; Suppose the rate of growth of bacteria in a Petri dish is given by q(t)=2t, where t is given in hours and q(t) is given in thousands of bacteria per hour. If a culture starts with 3,000 bacteria, find a function Q(t) that gives the number of bacteria in the Petri dish at any time t. How many bacteria are in the dish after 4 hours? Round your answer to the nearest thousand and do not include units.
Step-by-step explanation:
The detailed steps are as shown in the attachment.
q(t)=2t
dq/dt = 2t
Integrating both sides as shown in the attachment.
Any other question can be approached the same way.
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Answer:
Step-by-step explanation:
Let points D, E and F have coordinates and
1. Midpoint M of segment DF has coordinates
2. Midpoint N of segment EF has coordinates
3. By the triangle midline theorem, midline MN is parallel to the side DE of the triangle DEF, then points M and N are endpoints of the midsegment for DEF that is parallel to DE.
Answer:
Step-by-step explanation:
Area of the figure = area of the down triangle + area of trapezium + area of the upper triangle
Down triangle:
Base b = 8 in
Height = 6 in
= 24 in²
Trapezium:
bases a = 4 in & b = 6 in
Height h = 5 in
= 25 in²
Area of the upper triangle:
Base b = 6 in
Height = (8 - 5) = 3 in
= 9 in²
Area of the figure = 24 + 25 + 9 = 58 in²