Would an experience downhill skier want the slope of the hill to be 1/10 or 9/10? Why?

Mathematics

1 answer:

kolezko [41]3 years ago

8 0

Answer:

9/10

Step-by-step explanation:

step 1

Compare the slopes

$1/10=0.10$

$9/10=0.9$

$0.9 > 0.10$

therefore

An experienced skier would like the 9/10 hill slope because it is steeper, while the 1/10 is a softer slope.

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Change the fraction w-3/w+5 into an equivalent fraction with the denominator w2 + w – 20.

viktelen [127]

ANSWER

$\frac{ {w}^{2} - 7w + 12}{ {w}^{2} + w - 20 }$

EXPLANATION

The given fraction is,

$\frac{w - 3}{w + 5}$

To get an equivalent fraction, we multiply both the numerator and the denominator by the same quantity that will give us

w²+w-20

in the denominator.

This implies that,

$\frac{w - 3}{w + 5} = \frac{(w - 3)(w - 4)}{(w + 5)(w - 4)}$

We multiply out the numerators and denominators using the distributive property to obtain,

$\frac{w - 3}{w + 5} = \frac{ {w}^{2} - 4w - 3w + 12}{ {w}^{2} - 4w + 5w - 20 }$

This simplifies to

$\frac{w - 3}{w + 5} = \frac{ {w}^{2} - 7w + 12}{ {w}^{2} + w - 20 }$

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3 years ago

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3 years ago

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How do I graph the parabola?

scoundrel [369]

First of all, find a program or a calculator that will give you the answer. Then you'll know how to make your table. I recommend Desmos. I have inserted the final graph for you.

Make up a table for this graph. Put the lowest point as the central entry in your graph.

x y
-4
-3
-2
-1
0
Now fill in the y values.

x y
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-2 -5
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You can use the outline of the parabola and then mark the outline with the points in the table.

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3 years ago

HELP A.S.A.P!!!! The data to represent average test scores for a class of 16 students includes an outlier value of 78. If the ou

kolezko [41]

When the outlier is removed The mean would increase.

<u>Step-by-step explanation:</u>

Outliers are the value that lies outside the set of data. i.e. the data doesn't fit in the group.

Removing outliers can affect mean more than median. Because outlier removal sometimes affect the median but in a small percentage or sometimes it will remain the same.

Let us prove, consider 16 values one with 78 and other 15 with values nearly 85, 84 that will give the mean value as 84.

78, 84, 82, 86, 84, 85, 83, 86, 82, 85, 84, 83, 86, 85, 86, 85.

Mean = $\frac{Sum of the values}{Number of values}$ .