Answer:ype your answer here: Conclusions What conclusions can you draw about the identity of the unknowns? Write an evidence-based claim. Type your answer here: Evaluate the

Explanation:

6 0

2 years ago

could you please explain operations with scientific notation using this example. 5 × 10³ + 4.3 × 10⁴ i dont understand how to so

TEA [102]

Explanation:

The scientific notation:

$a\times10^k$

where

$1\leq a$ and k is integer.

We have the example:

$(5\times10^3)+(4.3\times10^4)$

You can write the numbers in a "normal" form:

$5\times10^3=5\times1000=5000\\\\4.3\times10^4=4.3\times10000=43000$

Make the sum:

$5000+43000=48000$

And next write it in the scientific notation:

$48000=4\underbrace{8000}_{\leftarrow4}=4.8000\times10000=4.8\times10^4$

<h3>Other method:</h3>

You can add numbers in scientific notation if the power of tens in both number is the same.

Therefore you must convert the first number:

$5\times10^3=0.5\times10\times10^3=0.5\times10^4$

Now, you can make the sum:

$(5\times10^3)+(4.3\times10^4)=0.5\times10^4+4.3\times10^4=(0.5+4.3)\times10^4=4.8\times10^4$

4 0

3 years ago

calculate atomic weight of silver which has two isotopes with the following properties : silver-107 (106.91 amu, 51.84% natural

Julli [10]

Answer: The atomic weight of silver is 107.87 amu

Explanation:

Mass of isotope silver-107 = 106.91 amu

% abundance of isotope silver -107 = 51.84% = $\frac{51.84}{100}=0.5184$

Mass of isotope silver-109 = 108.90 amu

% abundance of isotope silver-109 = 48.16% = $\frac{48.16}{100}=0.4816$

Formula used for average atomic mass of an element :

$\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})$

$A=\sum[(106.91\times 0.5184)+(108.90\times 0.4816)]$

$A=107.87amu$

Thus atomic weight of silver is 107.87 amu

8 0

4 years ago