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aleksandrvk [35]
3 years ago
5

A sentence for desert

Chemistry
2 answers:
Tanya [424]3 years ago
5 0
He knew he was in the desert when he saw the dust blowing and a cactus. /// He was trying to desert the field in which was dangerous.
Taya2010 [7]3 years ago
4 0
The desert was really hot. <--sand desert or. leaving something---> in the war, the people had to desert the land.
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When the following equation is balanced, what is the coefficient for HBr?
deff fn [24]
D.) Balanced equation is Zn + 2HBr - - - > ZnBr2 + H2.
4 0
3 years ago
How many grams of aluminum are needed to react completely with 1.2 mol of FeO?
a_sh-v [17]

Answer:

5

Explanation:

all you do is the math expression

4 0
2 years ago
Three carbon atoms are linked by single covalent bonds such that they form the shape of a V. All of the unshared electrons form
Nostrana [21]

Answer:

C) 8

Explanation:

Total number of carbon atoms = 3

Number of single bonds = 3

So, each carbon is bonded to the next carbon with the single bond, Number of unshared electrons left with the terminate carbons are 3 and with the intermediate carbon is 2.

Thus, the two terminate carbon have 3 hydrogen each and the intermediate will have 2.

<u>Total - 8</u>

6 0
3 years ago
Consider the reaction: N2(g) + O2(g) ⇄ 2NO(g) Kc = 0.10 at 2000oC Starting with initial concentrations of 0.040 mol/L of N2 and
IrinaVladis [17]

Answer:

0.011 mol/L

Explanation:

This can be solved with something called an ICE table.

I = initial

C = change

E = equilibrium

Initially, there is 0.04 M of N₂, 0.04 M of O₂, and 0 M of NO.

x amount of N₂ reacts.  Since the stoichiometry is 1:1, x amount of O₂ also reacts.  This produces 2x of NO.

After the reaction, there is 0.04-x of N₂, 0.04-x of O₂, and 2x of NO.

Here it is in table form:

\left[\begin{array}{cccc}&N2&O2&NO\\I&0.04&0.04&0\\C&-x&-x&+2x\\E&0.04-x&0.04-x&2x\end{array}\right]

Now we can use the equilibrium constant:

Kc = [NO]² / ( [N₂] [O₂] )

Substituting:

0.10 = (2x)² / ( (0.04 - x) (0.04 - x) )

Solving:

0.10 = (2x)² / (0.04 - x)²

√0.10 = 2x / (0.04 - x)

(√0.10) (0.04 - x) = 2x

(√0.10)(0.04) - (√0.10)x = 2x

(√0.10)(0.04) = 2x + (√0.10)x

(√0.10)(0.04) = (2 + √0.10)x

x = (√0.10)(0.04) / (2 + √0.10)

x = 0.0055

At equilibrium, the concentration of NO is 2x.  So the answer is:

[NO] = 2x

[NO] = 0.011

The equilibrium concentration of NO is 0.011 mol/L.

3 0
3 years ago
how would you write equation to show how buffers H2CO3 and NaHCO3 behave when (a) HCl is added and (b) NaOH is added.
Vlad1618 [11]
<span>H2CO3 <---> H+ + HCO3-
NaHCO3 <---> Na+ + HCO3-

When acid is added in the buffer, the excess H+ of that acid reacts with HCO3- to form H2CO3, and due to this NaHCO3 dissociates into HCO3- to attain the equilibrium. and hence there is no net effect of H+ due to pH remain almost constant. when a base is added to the buffer, the OH- ion of base react eith H+ ion present in buffer, then to attain equilibrium of H+ ion, the H2CO3 dissociates to produce H+ ion, but now there is the excess of HCO3- due to which Na+ ion react with them to attain equilibrium of HCO3-. hence there is again no net change in H+ ion due to which pH remain constant.....</span>
8 0
3 years ago
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