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nexus9112 [7]
3 years ago
15

Im bored, start conversation ;)​

Physics
2 answers:
lutik1710 [3]3 years ago
7 0
Uuhhh ok Hi I’m Aurora
Zielflug [23.3K]3 years ago
4 0

Answer:

hola

Explanation:

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What work do you think is done when you carry a 20 N weight backpack for a 1000 m walk? will the work be positive, negative, or
dezoksy [38]

The work done is positive and is equal to 20000 J

<h3>What is work done?</h3>

Work done is defined as the product of force and the distance moved by the force.

Mathematically:

  • Work done = force * distance

The work done by the force = 20 * 1000 = 20000J

The work done is positive and is equal to 20000 J

Learn more about work done at: brainly.com/question/25923373

#SPJ1

8 0
2 years ago
Describe how resistance affects the flow of current in a circuit
Sergeu [11.5K]

Resistance decreases the flow of current in a circuit.

Explanation:

The resistance of an electrical circuit is defined as the opposition to the flow of current in that particular circuit

4 0
3 years ago
Which substance would require the most heat to melt 100 g of the substance?
IrinaVladis [17]
Assuming all the substances are already at the temperature that is their melting point, we only need to worry about the heat required to change state, not the heat required to change temperature.

No calculations necessary for this question - just look at the latent heat of fusion. The higher this value, the more heat required per unit mass of the substance to melt it. Of the four answer options, aluminum has the highest value and therefore will take the most heat to melt the same mass.
3 0
3 years ago
A BODY STARTING FROM REST MOVES WITH CONSTANT ACCELERATON. what is the ratio of distance covered by the body during the fifth se
Art [367]

Answer:

9/25

Explanation:

Distance covered in the first 5 seconds:

Δx = v₀ t + ½ at²

Δx₀₋₅ = (0) (5) + ½ a (5)²

Δx₀₋₅ = 25a/2

Distance covered in the first 4 seconds:

Δx = v₀ t + ½ at²

Δx₀₋₄ = (0) (4) + ½ a (4)²

Δx₀₋₄ = 8a

So the distance covered during the 5th second is:

Δx₅ = 25a/2 − 8a

Δx₅ = 9a/2

So the ratio of the distance covered during the 5th second to the distance covered in the first 5 seconds is:

Δx₅ / Δx₀₋₅

(9a/2) / (25a/2)

9/25

8 0
3 years ago
I'm really tired so please help
Taya2010 [7]

So that the bridge doesn't break when the summer comes and It expands Or when winter comes and it contracts

3 0
3 years ago
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