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3 years ago

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An n- channel enhancement- mode MOSFET with 50 nm thick HfO2 high- k gate dielectric (Pr = 25) has a flat band voltage of 0.5 V,

and substrate doping of 1018 cm-3. The intrinsic carrier concentration is 1011 cm-3, effective electron channel mobility is 250 cm2/Vs, and Pr = 15. What is the drive current for a 50 om wide and 2 om long device at VG = 3 V and VD = 0.05 V? What is the saturation current at this gate bias?

1 answer:

Alexeev081 [22]3 years ago

4 0

Answer:

Find the complete solution in the given attachments

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Consider the diffusion of water vapor through a polypropylene (PP) sheet 1 mm thick. The pressures of H2O at the two faces are 3

Neko [114]

Answer:

$\boxed{0.000000266 \frac {cm^{3}.STP}{cm^{2}.s}}$

Explanation:

Diffusion flux of a gas, J is given by

$J=P_m\frac {\triangle P}{\triangle x}$ where $P_m$ is permeability coefficient, $\triangle$ P is pressure difference and x is thickness of membrane.

The pressure difference will be 10,000 Pa- 3000 Pa= 7000 Pa

At 298 K, the permeability coefficient of water vapour through polypropylene sheet is $38\times 10^{-13}(cm^{3}. STP)(cm)/(cm^{2}.s.Pa)$

Since the thickness of sheet is given as 1mm= 0.1 cm then

$J=38\times 10^{-13}(cm^{3}. STP)(cm)/(cm^{2}.s.Pa)\times \frac {7000 pa}{0.1cm}=0.000000266 \frac {cm^{3}.STP}{cm^{2}.s}$

Therefore, the diffusion flux is $\boxed{0.000000266 \frac {cm^{3}.STP}{cm^{2}.s}}$

7 0

3 years ago

A rigid tank with a total volume of 0.05 m3 initially contains a two-phase liquid-vapor mixture of water at a pressure of 15 bar

Westkost [7]

Answer:

a) $m_{2} = 0.753\,kg$ , b) $Q_{in} = 2122.963\,kJ$

Explanation:

A rigid tank means a storage whose volume is constant. Process is entirely isobaric. Initial and final properties of water are included below:

State 1 - Gas-Vapor Mixture

$P = 1500\,kPa$

$T = 198.29^{\textdegree}C$

$\nu = 0.02726\,\frac{m^{3}}{kg}$

$u = 1192.94\,\frac{kJ}{kg}$

$h_{g} = 2791.0\,\frac{kJ}{kg}$

$x = 0.2$

State 2 - Gas-Vapor Mixture

$P = 1500\,kPa$

$T = 198.29^{\textdegree}C$

$\nu = 0.06643\,\frac{m^{3}}{kg}$

$u = 1718.12\,\frac{kJ}{kg}$

$h_{g} = 2791.0\,\frac{kJ}{kg}$

$x = 0.5$

The model for the rigid tank is created by using the First Law of Thermodynamics:

$Q_{in} - (m_{1}-m_{2})\cdot h_{g} = m_{2}\cdot u_{2}-m_{1}\cdot u_{1}$

Initial and final masses are:

$m_{1} = \frac{V_{1}}{\nu_{1}}$

$m_{1} = \frac{0.05\,m^{3}}{0.02726\,\frac{m^{3}}{kg} }$

$m_{1} = 1.834\,kg$

$m_{2} = \frac{V_{2}}{\nu_{2}}$

$m_{2} = \frac{0.05\,m^{3}}{0.06643\,\frac{m^{3}}{kg} }$

$m_{2} = 0.753\,kg$

a) The final mass within the tank is:

$m_{2} = 0.753\,kg$

b) The total amount of heat transfer is:

$Q_{in} = m_{2}\cdot u_{2}-m_{1}\cdot u_{1}+ (m_{1}-m_{2})\cdot h_{g}$

$Q_{in} = (0.753\,kg)\cdot (1718.12\,\frac{kJ}{kg} )- (1.834\,kg)\cdot (1192.94\,\frac{kJ}{kg} ) + (1.081\,kg)\cdot (2791.0\,\frac{kJ}{kg} )$

$Q_{in} = 2122.963\,kJ$

5 0

3 years ago

Relation between Poisson's ration, young's modulus, shear modulus for an isotropic material

poizon [28]

Answer:

E=2 G(1+2μ)

Explanation:

Isotropic material :

Those material have same property in all direction is known as isotropic material.

Homogeneous material :

Those material have same property through out the volume is known as homogeneous material.

Relationship between Poisson ratio ,young modulus and shear modulus:

E=2 G(1+2μ)

Relationship between Poisson ratio ,bulk modulus and shear modulus:

E=2 K(1-μ)

Where

E is young modulus.

G is shear modulus.

μ is Poisson ratio.

8 0

3 years ago

A 240V single phase 6000 W heavy duty commercial electric heater runs constantly for 36 hours. If electricity cost $0.13/kWh, ho

Aloiza [94]

Answer:

A. $28

Explanation:

We have the load to be 240V

6000W will be converted to kilowatts

6000/1000 = 6kW

Time heater runs for 36 hours

Cost of electricity = $0.13/Kwh

The question needs us to find cost of running this electric heater

Total kilowatts

= 6kw x 36 hours

= 216kwh

Then the total cost = 216 x $0.13

= 28.08

= $28

5 0

3 years ago

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Large quantities of liquefied natural gas (LNG) are shipped by ocean tanker. At the unloading port, provision is made for vapori

kodGreya [7K]

Answer:

yfyuhvckydfxcvkjyfvgrjfvhkhgfyhtfhchghjgyfvyghvhygvkuh

Explanation:

6 0

3 years ago