The statement is true as all Ionic compounds are called Electrolytes because they dissociate(break apart) in water to form a solution that conducts electric current.
Explanation:
An ionic compound also called an electrolyte. Ionic compounds have capability to get dissociate into water to give ions(cation and anion) which conduct electric current. This process is called conductivity.
Some insoluble compounds that are not dissolved in water still they form ions which conduct electricity.
The cations and anions released are responsible for carrying current.
Strong acids and strong bases are the strong electrolytes as they dissociate to give more ions as NaOH, HCl.
The cations move to the cathode and anions towards the anode. Cation and anion movement in the solution is electric current.
Answer:
Solution of isopropanol is 10.25 molal
Explanation:
615 g of isopropanol (C3H7OH) per liter
We gave the information that 615 g of solute (isopropanol) are contained in 1L of water. We need to find out the mass of solvent, so we use density.
Density of water 1g/mL → Density = Mass of water / 1000 mL of water
Notice we converted the L to mL
Mass of water = 1000 g (which is the same to say 1kg)
Molality are the moles of solute in 1kg of solvent, so let's convert the moles of isopropanol → 615 g . 1mol / 60g = 10.25 moles
Molality (mol/kg) = 10.25 moles / 1kg = 10.25 m
Answer:
Explanation:
Hello!
In this case, given the chemical reaction:
In such a way, given the volumes and molarities of each reactant, we can compute the moles of produced iron (III) hydroxide by each of them, via the 3:1 and 1:1 mole ratios:
It means that the sodium hydroxide is the limiting reactant and 0.00833 moles of iron (III) hydroxide are produced; thus, the required mass is:
Answer:
HC₂H₃O₂/KC₂H₃O₂
Explanation:
Considering the Henderson- Hasselbalch equation for the calculation of the pH of the basic buffer solution as:
For a best pair, the pKa value must be equal to pH.
NH₃/NH₄Cl forms a basic buffer and cannot account for pH = 5
out of the acidic buffer given,
So, HF , Ka = 3.5 × 10⁻⁴ , So pKa = 3.46
HC₂H₃O₂ , Ka = 1.8 × 10⁻⁵ , So pKa = 4.77
<u>The best pair to show pH = 5 is HC₂H₃O₂/KC₂H₃O₂</u>
HI acts as an arrhenius acid in solution. It will dissociate into H⁺ and I⁻ therefore being a proton donor. (HI is actually one of the 7 strong acids)
I hope this helps.