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bulgar [2K]
8 months ago
8

I need help with with number 1515. How many moles of NO2 are in a 37.058 L container at 101.28 kPa and -139.86

Chemistry
1 answer:
Andre45 [30]8 months ago
5 0

Explanation:

To solve this question, we will use the Clayperon Equation:

P.V = n.R.T

where:

P = 101.28 kPa

1 atm = 101,325 Pa

x atm = 101,280 Pa

x = 1 atm

V = 37.058 L

n = we don't know

R = 0.082 atm.L/K.mol

T = -139.88 ºC = -139.88+273.15 = 133.27 K

1*37.058 = n*0.082*133.27

n = 0.29 moles

Answer: 0.29 moles

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First of all, this is the chemistry section, while your question is a physics question. Anyway I'll tell you how to solve it.

First we need to find the rate that the truck moves in a second.

1km = 1000m
40km = 40000m
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40000m/hr ÷ 60 = 666.66(repeating)/minute
1 minute = 60 seconds
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Next we simply multiply the speed of the truck by the number of seconds it travels.

11.11 × 5 = 55.55
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2 years ago
What is the percent error for the experiment if the actual density is
OLga [1]

Answer:

<h3>The answer is 40.96%</h3>

Explanation:

The percentage error of a certain measurement can be found by using the formula

P(\%) =  \frac{error}{actual \:  \: number}  \times 100\% \\

From the question

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We have the final answer as

<h3>40.96 %</h3>

Hope this helps you

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