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galben [10]
3 years ago
6

Calculate the fractional saturation for hemoglobin when the partial pressure of oxygen is 58 mm Hg. Assume hemoglobin is 50% sat

urated with oxygen at a partial pressure of 28 mm Hg and that the Hill coefficient is 3. Express your answer to two significant figures.
Chemistry
1 answer:
svetlana [45]3 years ago
4 0

Answer:

0.8988

Explanation:

To calculate the fractional saturation of hemoglobin , the formula used is

YO_2=\frac{(pO_2)^n}{(p50)^n+(pO_2)^n}

now putting the values

YO_2= \frac{58^3}{28^3+58^3}

= \frac{195112}{21952+195112}

=0.8988

Therefore, fractional saturation of hemoglobin= 0.8988

where

YO_2= fractional saturation of hemoglobin

pO_2= partial pressure of oxygen

p50= is the pO_2 at which hemoglobin is 50% saturated

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Answer: Fe<em>(aq)</em>+S<em>(aq)</em>=FeS<em>(s)</em>

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Each dissolved FeBr2 breaks up into one Fe with a charge of 2+ and two Br with a negative charge. This gives you:

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3.) Ionic formula: Fe(aq)+ <u>2Br(aq)</u>+<u>2 Na(aq)</u>+S (aq)=FeS(s)+<u>2 Na(aq)+2Br(aq)</u>

4.)When you've derived a total ionic equation (above), you'll  find that some ions appear on both sides of the equation in equal numbers. For example, in this case two Na cations and two Br anions appear on both sides of the total ionic equation. What does this mean? It means these ions don't participate in the chemical reaction. They're present before and after the reaction. Nothing happens to them. So those are removed and you're left with the net ionic: Fe(aq)+S(aq)=FeS(s)

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