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sammy [17]
3 years ago
9

Which processes are affected by freeze and thaw cycles

Chemistry
2 answers:
mr_godi [17]3 years ago
7 0

Answer:

A C D

Explanation:

galben [10]3 years ago
3 0

out of these choices:

creep

deposition

landslide

slump

weathering

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In water, Vanillin, C8H8O3, has a solubility of 0.070 moles of vanillin per liter of solution at 25C. What will be produced if 5
Rufina [12.5K]

Answer:

The full amount (5.00 g) will be dissolved in 1 L of water at 25°C.

Explanation:

The molecular weight (MW) of Vanillin (C₈H₈O₃) is calculated from the chemical formula as follows:

MW(C₈H₈O₃) = (12 g/mol x 8) + (1 g/mol x 8) + (16 g/mol x 3) = 152 g/mol

If 0.070 mol of C₈H₈O₃ are soluble per liter of water at 25°C, the maximum mass that can be dissolved in 1 L is:

0.070 mol x 152 g/mol = 10.64 g

Since 5.00 g is lesser than the maximum amount that can be dissolved (10.64 g), the added amount will be completely dissolved in 1 L of water at 25°C.

7 0
3 years ago
An increase in the temperature of reactant causes an increase in the rate of reaction.
tatyana61 [14]

Answer:

d) The fraction of collision with total kinetic energy larger than activation energy  increases.

Explanation:

Hello,

In this case, kinetic models explain how the rate of a chemical reaction is affected by several factors. In such a way, specifically for temperature, when it increases, the average velocity of the particles is also increased, for that reason, the collision frequency increases since the molecules are more likely to collide as they move faster and encounter to each other.

Nonetheless, it is the minor reason because the main reason is that the effective collisions increase when the temperature is increased, and they are related with the fraction of collision with total kinetic energy that turns out larger than the activation energy, therefore, answer is d).

Best regards.

7 0
4 years ago
What type of substance is magnesium carbonate?
tresset_1 [31]
Magnesium salt is the type of substance
7 0
3 years ago
Read 2 more answers
Consider the reaction: A <=> B. Under standard conditions at equiliubrium, the concentrations of the compounds are [A] = 1
Katen [24]

Answer:

Keq'>1\\\Delta G'

Explanation:

Hello,

In this case, for the given reaction, the equilibrium constant turns out:

Keq=\frac{[B]}{[A]}=\frac{0.5M}{1.5M} =1/3

Nonetheless, we are asked for the reverse equilibrium constant that is:

Keq'=\frac{1}{Keq}=3

Which is greater than one.

In such a way, the Gibbs free energy turns out:

\Delta G'=-RTln(Keq')\\

Now, since the reverse equilibrium constant is greater than zero its natural logarithm is positive, therefore with the initial minus, the Gibbs free energy is less than zero, that is, negative.

7 0
4 years ago
Read 2 more answers
Please help me out with these questions please!!!
iogann1982 [59]
Answer to the first one is that they are brittle. This is not true because they have strong bonds
7 0
3 years ago
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