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2 years ago

HELPPPPPP MEEEE‼️‼️‼️Use the equations from

Chemistry

1 answer:

Step2247 [10]2 years ago

8 0

1.180
2.-900
3.20
4.8
Hope this helps

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2Al + 3Br2 --> 2AlBr3

vlada-n [284]

A) The limiting reactant is Al
b) Br2 is the excess reactant
c) The amount moles of AlBr3 that get produced will be equal to the number of moles of Al to begin with.
d) 0

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2 years ago

How does energy flow through the food chain?

yuradex [85]

Answer:

2nd order.

Explanation:

gras, grasshopper, frog, snake, eagle

Pleas mark branliest if you are satisfied with the answer. Thanking you in anticipation.

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2 years ago

Read 2 more answers

Sodium chloride (NaCl) is commonly used to melt ice on roads during the winter. Calcium chloride (CaCl2) is sometimes used for t

mihalych1998 [28]

Answer:

$\Delta Tfp_{NaCl}= -14.0\°C\\\\\Delta Tfp_{CaCl_2}=-11.1\°C$

Explanation:

Hello!

In this case, since the freezing point depression caused by the addition of a solute, we use the following formula:

$\Delta Tfp= i*m*Kfp$

Thus, we first need to compute the molality of each solute, as shown below:

$m_{NaCl}=\frac{220.g/(58.44g/mol)}{1.00kg} =3.76m\\\\m_{CaCl_2}=\frac{220.g/(110.98g/mol)}{1.00kg} =1.98m$

Next, since NaCl has two ionic species, one Na⁺ and one Cl⁻, and CaCl₂ three, one Ca²⁺ and two Cl⁻, the van't Hoff's factors are 2 and 3 respectively, therefore the freezing point depressions turn out:

$\Delta Tfp_{NaCl}= 2*3.76m*-1.86\°C/m=-14.0\°C\\\\\Delta Tfp_{CaCl_2}= 3*1.98m*-1.86\°C/m=-11.1\°C$

It means that CaCl₂ is still better than NaCl because produces involves a higher melting point for the ice, so it would melt faster.

Best regards!

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2 years ago

Which is a factor in determining the average atomic mass of an element

shtirl [24]

The mass numbers of the different isotopes of that element are averaged according to their respective abundances in nature.

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2 years ago

If there is a loss of 5.63 x 10-7kg of mass in a nuclear reaction, how many Joules of energy would be released? Recall that c =

Fudgin [204]

Thank you for posting your question here at brainly.

E = mc^2
where E is the energy in joules, 
m is the mass in kilograms, 
and c is the speed of light. 

E = mc^2 
E = (5.63 x 10^-7 kg)(3 x 10^8 m/s)^2 
E = 5.07 x 10^10 J

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3 years ago