Consider an experiment with the same goals as the one you performed, but a

An object on Earth weighs 600 N and on Mars 100 N. If its mass on Earth is approximately 60 kg what is the mass of the object on

Deffense [45]

Answer:

I think its

10 kg

plzz plzz plzz. mark as brainliest

6 0

3 years ago

If at 10m above the ground an object has 50J of Kinetic Energy, with 50J of Potential Energy. How high can the object travel?

steposvetlana [31]

Hi there!

$\large\boxed{\text{B) 20 meters}}$

We know that:

$E_T = U + K$

U = Potential Energy (J)

K = Kinetic Energy (J)

E = Total Energy (J)

At 10m, the total amount of energy is equivalent to:

U + K = 50 + 50 = 100 J

To find the highest point the object can travel, K = 0 J and U is at a maximum of 100 J, so:

100J = mgh

We know at 10m U = 50J, so we can solve for mass. Let g = 10 m/s².

50J = 10(10)m

m = 1/2 kg

Now, solve for height given that E = 100 J:

100J = 1/2(10)h

100J = 5h

h = 20 meters

3 0

3 years ago

A 4.30 g bullet moving at 943 m/s strikes a 730 g wooden block at rest on a frictionless surface. The bullet emerges, traveling

Ymorist [56]

Answer:

(a)2.7 m/s

(b) 5.52 m/s

Explanation:

The total of the system would be conserved as no external force is acting on it.

Initial momentum = final momentum

⇒(4.30 g × 943 m/s) + (730 g × 0) = (4.30 g × 484 m/s) + (730 g × v)

⇒ 730 ×v = (4054.9 - 2081.2) =1973.7

⇒v=2.7 m/s

Thus, the resulting speed of the block is 2.7 m/s.

(b) since, the momentum is conserved, the speed of the bullet-block center of mass would be constant.

$V_{COM} = \frac{m_b}{m_b+m_{bl}}v_{bi}=\frac{4.30}{4.30+730}\times 943 m/s = 5.52 m/s$

Thus, the speed of the bullet-block center of mass is 5.52 m/s.

4 0

4 years ago

To protect their young in the nest, peregrine falcons will fly into birds of prey (such as ravens) at high speed. In one such ep

I am Lyosha [343]

Answer:

Part a)

$\theta = 48 degree$

Part b)

$v = 13.45 m/s$

Explanation:

Part a)

mass of the Falcon bird is given as

$m = 600 g$

initial speed of the bird is

$v_i = 20 m/s$

final speed of the bird is given as

$v_f = 5 m/s$ (opposite direction)

So here the impulse given by falcon bird is given as

$I = m(v_f - v_i)$

$I = 0.600(20 + 5)$

$I = 15 kg m/s$

now the final momentum of Raven bird in perpendicular direction is given as

$I = mv_y$

$15 = 1.50 v_y$

$v_y = 10 m/s$

now the change in the angle of the raven bird is given as

$tan\theta = \frac{v_y}{v_x}$

$tan\theta = \frac{10}{9}$

$\theta = 48 degree$

Part b)

Final speed of the raven bird is given as

$v^2 = v_x^2 + v_y^2$

$v^2 = 9^2 + 10^2$

$v = 13.45 m/s$

5 0

3 years ago

When a hypothesis is wrong, scientists often begin by revising the (blank)

Vsevolod [243]

I might be wrong, but. The words seem to fit.

When a hypothesis is wrong, scientists often begin by revising the question after that, its common for scientists to redesign the experiment.

7 0

3 years ago

Read 2 more answers