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lapo4ka [179]
4 years ago
14

In which reaction is a precipitation occurring

Chemistry
1 answer:
iogann1982 [59]4 years ago
6 0

It is reacting as a chemical reaction .

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What is the compound name of 3h20
Feliz [49]
Trihydrate - basically 3 molecules of water. Unless you're referring to the molecule 3H2O used in measuring the total body water in the case it tritiated water.
8 0
3 years ago
A 575.4575.4 mL sample of carbon dioxide was heated to 377377 K. If the volume of the carbon dioxide sample at 377377 K is 824.7
Margaret [11]

Answer:

263 K

Explanation:

Assuming ideal behaviour and constant pressure, we can solve this problem by using Charles' law, which states that at constant pressure:

  • T₁V₂=T₂V₁

In this case:

  • T₁ = ?
  • V₂ = 824.7 mL
  • T₂ = 377 K
  • V₁ = 575.45 mL

We <u>input the data</u>:

  • T₁ * 824.7 mL = 377 K * 575.45 mL

And <u>solve for T₁</u>:

  • T₁ = 263 K
3 0
3 years ago
3. Heating the copper product at too high a temperature in an oxygen atmosphere results in the formation of copper( )oxde, . Wri
olya-2409 [2.1K]
First, write the equation:
Cu + O2 -> CuO
Now, balance:
2 Cu + O2 -> 2 CuO
6 0
3 years ago
Write a balanced half-reaction for the product that forms at each electrode in the aqueous electrolysis of the following salts:(
Semmy [17]

The balanced half-reaction for the product that forms at anode is Fe⁺² + 2e⁻ → Fe(s) and 2H₂O + 2e⁻ → H₂ + 2OH⁻, the product that forms at cathode is 2I⁻  → I₂ + 2e- and 2H₂O  → O₂ + 4H⁺ + 4e⁻  

<h3>What is Balanced Chemical Equation ?</h3>

The equation during which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation is called balanced chemical equation.

Now write the equation for FeI₂

At cathode:

Fe⁺² + 2e⁻ → Fe(s) Eo = - 0.44 V

2H₂O + 2e⁻ → H₂ + 2OH⁻ Eo = - 0.827 V

It is easy to decrease Fe⁺² ions than the water, the product which is formed at cathode is Iron.

At anode:

2I⁻  → I₂ + 2e-    Eo = - 0.54 V

2H₂O  → O₂ + 4H⁺ + 4e⁻    Eo = -1.23 V

O₂ gas formed at anode.

Thus from the above conclusion we can say that The balanced half-reaction for the product at anode is Fe⁺² + 2e⁻ → Fe(s) and 2H₂O + 2e⁻ → H₂ + 2OH⁻, the product that forms at cathode is 2I⁻  → I₂ + 2e- and 2H₂O  → O₂ + 4H⁺ + 4e⁻.

Learn more about the Balanced chemical equation here: brainly.com/question/26694427

#SPJ4

6 0
2 years ago
What mass is in 5 moles of helium?
ArbitrLikvidat [17]

Answer:

Mass = 20 g

Explanation:

Given data:

Number of moles of He = 5 mol

Mass of He = ?

Solution:

Formula:

Number of moles = mass/ molar mass

Molar mass = 4 g/mol

by putting values,

5 mol = Mass / 4 g/mol

Mass = 5 mol × 4 g/mol

Mass = 20 g

3 0
3 years ago
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