Aluminum sulfide is Al₂S₃, which shows that there are 3
sulfur atoms per formula unit.

In one mole there is Avogadro’s number of atoms and Avogadro’s
number = 6.02 x 10²³

In 1.10 mole = 1.10 x 6.02x10²³ = 6.62 x 10²³ formula units

Now multiply with 3 to get number of sulfur atoms present in
1.10 mol of Aluminum sulfide;

3 x 6.62x10²³ = 1.99 x 10²⁴

So, the answer is 1.99 x 10²⁴ sulfur atoms.

**Answer:**

They are very reactive, electropositive, monovalent metals forming strongly alkaline hydroxides.

**Explanation:**

any of the elements lithium, sodium, potassium, rubidium, cesium, and francium, occupying Group IA

Becouse melting point and cooling point are two opposite things one is 100degrees nd other 0degrees

**Answer:**

Systems of measurement in use include the International System of Units (SI), the modern form of the metric system, the imperial system, and United States customary units.