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Bumek [7]
3 years ago
8

Forms a new substance with different chemical and physical properties. What change would most likely occur?

Chemistry
1 answer:
Maksim231197 [3]3 years ago
6 0
When new substance forms with different chemical and physical properties mostly a chemical change occurs.
hope it helps
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Arya drops a small sample of brown iodine into a beaker of water.
kiruha [24]
A the iodine spreads evenly throughout the water
8 0
4 years ago
Adaptations result from interactions between organisms and their___.
sineoko [7]

Answer: Environment

Explanation:

Organisms can be placed in an environment not like their own, but can learn to adapt by exploring and interacting with the new environment.

8 0
3 years ago
what is the molarity of a solution made by dissolving 18.5 grams of NaCL into enough water to reach 450.0ML​
ValentinkaMS [17]

Answer:

0.702M

Explanation:

Molarity of a solution, which refers to the molar concentration of that solution can be calculated thus;

Molarity = number of moles (n) ÷ volume (V)

Firstly, we convert 18.5 grams of NaCl to moles using the formula; mole = mass/molar mass

molar mass of NaCl = 23 + 35.5 = 58.5g/mol

mole = 18.5/58.5

mole = 0.32moles

Volume of water (V) = 450mL = 450/1000 = 0.450L

Molarity = n/V

Molarity = 0.32/0.450

Molarity = 0.702M

4 0
3 years ago
A water treatment plant applies chlorine for disinfection so that 10 mg/L chlorine is achieved immediately after mixing. The vol
Vlada [557]

<u>Answer:</u> The mass of chlorine needed by the plant per day is 9.4625\times 10^8mg

<u>Explanation:</u>

We are given:

Volume o water treated per day = 25,000,000 gallons

Converting this volume from gallons to liters, we use the conversion factor:

1 gallon = 3.785 L

So, \frac{3.785L}{1\text{ gallon}}\times 25,000,000\text{ gallons}=9.4625\times 10^7L

Amount of chlorine applied for disinfection = 10 mg/L

Applying unitary method:

For 1 L of water, the amount of chlorine applied is 10 mg

So, for 9.4625\times 10^7L of water, the amount of chlorine applied will be \frac{10mg}{1L\times 9.4625\times 10^7L}=9.4625\times 10^8mg

Hence, the mass of chlorine needed by the plant per day is 9.4625\times 10^8mg

6 0
3 years ago
What is the percent composition in chloric acid (HClO3)?
Nuetrik [128]
Total weight = 1 + 35.45 + 3 * 16 = 84.45

H = 1 / 84.45 * 100% = 1.18%
Cl = 35.45 / 84.45 * 100% = 41.98%
O = 48 / 84.45 * 100% = 56.84%
7 0
3 years ago
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