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raketka [301]
3 years ago
8

What would be your estimate of the age of the universe if you measured a value for Hubble's constant of H0 = 30 km/s/Mly ? You c

an assume that the expansion rate has remained unchanged during the history of the universe.
Physics
1 answer:
Maksim231197 [3]3 years ago
6 0

Answer:

The age of the universe would be 9.9 billion years

Explanation:

We can calculate an estimate for the age of the Universe from Hubble's Law. Let's suppose the distance between two galaxies is D and the apparent velocity with which they are separating from each other is v. At some point, the galaxies were touching, and we can consider that time the moment of the Big Bang.

Thus, the time it has taken for the galaxies to reach their current separations is:

\displaystyle{t=D/v}

and from Hubble's Law:

v =H_0D

Therefore:

\displaystyle{t=D/v=D/(H_0\times D)=1/H_0}

With the given value for the Hubble's constant we have:

H_0=(30\ km/s/Mly) \times (1 Mly/ 9.461 \times 10^{18} km) = 3.17\times 10^{-18}\ 1/s

and thus,

t=1/H_0 = 1/(3.17\times 10^{-18} 1/s) = 0.315 \times 10^{18}\ s \approx 9988584474.8858\ years \approx 9.9\ billion\ years

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Answer:

4

Explanation:

8 0
3 years ago
A farm tractor tows a 3300-kg trailer up a 14" incline with a steady speed of 2.8 m/s. what force does the tractor exert on the
gladu [14]

The force exerted by gravity is:

F = m g

F = 3300 kg * 9.8 m/s^2

F = 32,430 N

 

The force exerted due to the inclined plane is:

F tractor = 32,430 N * sin 14

<span>F tractor = 7,823.75 N      (answer)</span>

7 0
3 years ago
A rope of total mass m hnd length L is suspended vertically with an object of mass M suspended from the lower end. Find an expre
pantera1 [17]

Answer:

Part a)

v = \sqrt{xg + \frac{MLg}{m}}

Part b)

t = 12 s

Explanation:

Part a)

Tension in the rope at a distance x from the lower end is given as

T = \frac{m}{L}xg + Mg

so the speed of the wave at that position is given as

v = \sqrt{\frac{T}{\mu}}

here we know that

\mu = \frac{m}{L}

now we have

v = \sqrt{\frac{ \frac{m}{L}xg + Mg}{m/L}

v = \sqrt{xg + \frac{MLg}{m}}

Part b)

time taken by the wave to reach the top is given as

t = \int \frac{dx}{\sqrt{xg + \frac{MLg}{m}}}

t = \frac{1}{g}(2\sqrt{xg + \frac{MLg}{m}})

t = \frac{2}{9.8}(\sqrt{(39.2\times 9.8) + \frac{8(39.2)(9.8)}{1}})

t = 12 s

4 0
3 years ago
Do you think there could be another period of time when so many brilliant discoveries are made in such a span of time? Why or Wh
Arada [10]

There won't be another period where many brilliant discoveries are made in such a span of time because of the high degree of advancement already.

<h3>What is Technology?</h3>

Tgis is defined as the application of scientific knowledge for practical purposes.

We have advanced technological advancement which is why there won't be many discoveries in such time span.

Read more about Technology hee brainly.com/question/7788080

8 0
2 years ago
A circle graph shows that one-fourth of the students in a particular school ride the bus every day. What is this equivalent meas
Aleonysh [2.5K]

Answer:

it's 1.57... radians and 90°

3 0
3 years ago
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