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ANTONII [103]
3 years ago
6

Two small identical balls A and B are held a distance r apart on a frictionless surface, with i very large compared with the siz

e of the balls. Ball A has a net charge of2q; ball B has a net charge of q. The balls are released at the same instant and begin to move together. Which characteristics describe the magnitudes of their accelerations over time? point Oequal and increasing Ounequal and increasing Oequal and decreasing Oequal and constant
Physics
1 answer:
iren2701 [21]3 years ago
4 0

According to the statement both bodies will experience the same force, by the effect of action and reaction, which would be the same to apply Newton's third law. By the characteristics presented both will have the same mass and the same acceleration. However, considering the sign of their charges, these being the same, they will be repelled from each other. When this movement is generated, the force will begin to decrease as the distance increases and therefore its acceleration will also decrease

Hence the correct option is equal and decreasing.

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A lunar module weighs 12 metric tons on the surface of the Earth. How much work is done in propelling the module from the surfac
zhuklara [117]

Answer:

W=76.55 miles.metric tons

Explanation:

Given that

Weight on the earth = 12 tons

So weight on the moon =12/6 = 2 tons

 ( because at moon g will become g/6)

As we know that

F=\dfrac{K}{x^2}

Here x= 1100 miles

F 2 tons

2=\dfrac{K}{1100^2}

So

K=2.4\times 10^6

We know that

Work = F. dx

W=\int_{x_1}^{x_2}F.dx

W=\int_{1100}^{1140}\dfrac{2.4\times 10^6}{x^2}.dx

W=-2.4\times 10^6\left[\dfrac{1}{x}\right]_{1100}^{1140}

W=-2.4\times 10^6\left[\dfrac{1}{1140}-\dfrac{1}{1100}\right]

W=76.55 miles.metric tons

6 0
3 years ago
Web Spiders and Oscillations All spiders have special organs that make them exquisitely sensitive to vibrations. Web spiders det
chubhunter [2.5K]

Complete Question

The complete quetion is shown on the first uploaded image

Answer:

Explanation:

From the question we are told that

       The mass of the fly is  m_f =  11 mg =  11*10^{-3} g =  1.1*10^{-5} \ kg

        The extension of the web is  e=  4.00 \ mm = 0.004 \ m

       

The spring constant is mathematically evaluated as

          k = \frac{mg}{e}

substituting values

        k = \frac{1.1 *10^{-5} *9.8}{0.004}

         k = 0.027 \ N/m

The frequency of vibration is

         f =  \frac{1}{2 \pi} \sqrt{\frac{k}{m} }

substituting values

       f =  \frac{1}{2 * 3.142 } \sqrt{\frac{0.027}{1.1*10^{-5}} }

      f = 7.9 Hz

         

8 0
3 years ago
What is Br charge after it gains an electron?
sergeinik [125]

Im not 100% sure but i think its bromine.

Hope this helps ^_^

4 0
3 years ago
A long copper rod of diameter 2.0 cm is initially at a uniform temperature of 100°C. It is now exposed to an air stream at 20°C
Lisa [10]

Answer:

t = 4.0 min

Explanation:

given data:

diameter of rod = 2 cm

T_1 = 100 degree celcius

Air stream temperature =  20 degree celcius

heat transfer coefficient = 200 W/m2. K

WE KNOW THAT

copper thermal conductivity = k = 401 W/m °C

copper specific heat Cp = 385 J/kg.°C

density of copper = 8933 kg/m3

charateristic length is given as Lc

Lc = \frac{V}{A_s}

Lc = \frac{\frac{\pi D^2}{4} L}{\pi DL}

Lc = \frac{D}{4}

Lc = \frac{0.02}{6} = 0.005 m

Biot number is given as Bi = \frac{hLc}{k}

Bi = \frac{200*0.005}{401}

Bi = 0.0025

As Bi is greater than 0.1 therefore lumped system analysis is applicable

so we have

\frac{T(t) - T_∞}{Ti - T_∞} = e^{-bt} ............1

where b is given as

b = \frac{ hA}{\rho Cp V}

b = \frac{ h}{\rho Cp Lc}

b = \frac{200}{8933*385*0.005}

b = 0.01163 s^{-1}

putting value in equation 1

\frac{25-20}{100-20} = e^{-0.01163t}

solving for t we get

t = 4.0 min

6 0
3 years ago
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erma4kov [3.2K]
The duck at 12m/s has a greater speed than the heron which travels at 10m/s
4 0
3 years ago
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