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3 years ago

What are close-toed shoes least likely to provide protection against?

Physics

2 answers:

Dennis_Churaev [7]3 years ago

8 0

Hydrogen gas is harmless to your feet so since you don’t need protection against it that seems the best answer.

VLD [36.1K]3 years ago

6 0

Answer: Hydrogen gas produced during a reaction

Explanation:

A chemical lab is a place where potential hazards oriented to the use of the chemicals can happen. These chemicals can cause injuries to the skin when come in contact directly or indirectly. Therefore, protective safety measures should be taken so as to protect oneself while working in a chemical lab.

Among the options given, hydrogen gas produced during a reaction is the correct option. This is because of the fact that close-toed shoes can provide protection against all types of chemical fluids. But the gases like hydrogen gas are reactive and they are permeable inside the shoe material hence, may cause damage.

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A uniform rod of mass M and length L can pivot freely at one end. Initially, the rod is oriented vertically above the pivot, in

Leya [2.2K]

Answer:

The speed of its center of mass = $\sqrt{\frac{3}{2}gL}$

Explanation:

Consider the potential energy at the level of center of mass of rod below the pivot=0

Mass of uniform rod=M

Length of rod=L

The rotational inertia about the end of a uniform rod= $\frac{1}{3}ML^2$

Kinetic energy at the level of center of mass of rod below the pivot= $\frac{1}{2}I\omega^2$

Kinetic energy at the level of center of mass of rod above the pivot=0

Potential energy at the level of center of mass of rod above the pivot=mgh

We have to find the center of mass ( in terms of g and L).

According to conservation of law of energy

Initial P.E+Initial K.E=Final P.E+Final K.E

$mgh+0=0+\frac{1}{2} I\omega^2$

Where $K.E=\frac{1}{2} I\omega^2$

I=Moment of inertia

$\omega$ =Angular velocity

Substitute the values then we get

$MgL=\frac{1}{2}\times \frac{1}{3}ML^2\omega^2$

$\omega^2=\frac{6g}{L}$

Now, we know that $\omega=\frac{v}{r}$ , $r=\frac{L}{2}$

Substitute the values then we get

$\frac{v^2}{(\frac{L}{2})^2}=\frac{6g}{L}$

$\frac{v^24}{L^2}=\frac{6g}{L}$

$v^2=\frac{6g\times L^2}{4L}$

$v^2=\frac{3gL}{2}$

$v=\sqrt{\frac{3}{2}gL}$

Hence, the speed of its center of mass = $\sqrt{\frac{3}{2}gL}$

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4 years ago

When one end of iron poker is put into the edge of a fire the other end of the poker gets hot due to what the heat transfers?

Greeley [361]

Answer:

The answer is B) Conduction

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3 years ago

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Explain why the roller coaster’s potential energy is greater at point 1 than at point 4.

lesya692 [45]

Point 1 is PROBABLY higher up than point 4.

Another possibility is that on the way from Point 1 to point 4,
a lot of people are falling out of the coaster.

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the picture that goes with this question. It's important.

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4 years ago

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Mekhanik [1.2K]

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3 years ago

Is a nucleus that absorbs at 4.13 δ more shielded or less shielded than a nucleus that absorbs at 11.45 δ?

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Explanation:

A nucleus that absorbs 11.45δ is less shielded than a nucleus that absorbs at 4.13δ.

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3 years ago