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rjkz [21]
3 years ago
12

BF needed Near raleigh

Chemistry
2 answers:
11111nata11111 [884]3 years ago
8 0

Answer:

no

Explanation:

Studentka2010 [4]3 years ago
4 0

Answer:

what

Explanation:

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Fill in the left side of this equilibrium constant equation for the reaction of benzoic acid with water
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<h3>C6H5CO2H (aq) + H2O (l) _C6H5CO2<em>-</em><em> </em><em>+</em><em> </em><em>H3O</em></h3>
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I need on that question at the bottom of the page?
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The hills and valleys decrease the height and speed of the ride. This means that the graph has a negative correlation.

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3 0
3 years ago
Which of the following are observations? Select all that apply.
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How many sigma and pi bond are there in naphthalene? ​
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7 0
1 year ago
Read 2 more answers
Read the given equation.
S_A_V [24]

Answer:

2.30 liters.

Explanation:

  • The balanced equation of the reaction is:

<em>Na₂O₂ + CO₂ → Na₂CO₃ + 1/2O₂,</em>

  • It is clear that 1.0 mole of Na₂O₂ reacts with 1.0 mole of CO₂ to produce 1.0 mole of Na₂CO₃ and 0.5 mole of O₂.
  • The no. of moles of CO₂ in (4.60 L) reacted can be calculated from the relation: <em>PV = nRT</em>.

P is the pressure of the gas (P = 1.0 atm at STP),

V is the volume of the gas (V = 4.60 L),

R is the general gas constant (R = 0.082 L.atm/mol.K),

T is the temperature of the gas (T = 273.0 K at STP).

∴ n = PV/RT = (1.0 atm)(4.6 L) / (0.082 L.atm/mol.K)(273.0 K) = 0.205 mol.

<u><em>Using cross multiplication:</em></u>

1.0 mole of CO₂ produces → 0.5 mole of O₂, from the stichiometry.

0.205 mole of CO₂ produces → ??? mole of O₂.

  • The no. of moles of O₂ produced from 4.60 L of CO₂ = (0.5 mole)(0.205 mole) / (1.0 mole) = 0.103 mole.
  • ∴ The volume of O₂ produced from 4.60 L of CO₂ = nRT/P = (0.103 mol)(0.082 L.atm/mol.K)(273.0 K) / (1.0 atm) = 2.30 liters.
7 0
2 years ago
Read 2 more answers
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