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PilotLPTM [1.2K]
2 years ago
12

How many moles of Cu2S can be formed from 11 moles of HCl?

Chemistry
1 answer:
natima [27]2 years ago
4 0

Answer:

hi

Explanation:

hi

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1st one is right..it helps filter waste inside the cell.

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A/an _______ bond allows metals to conduct electricity
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If gas is initially at 350L and 500k then changes to 295K what is the new volume
Dimas [21]
<h2>Hello!</h2>

The answer is:

The new volume is equal to 206.5 L.

<h2>Why?</h2>

To solve this problem, we need to assume that the pressure is constant, and use the Charle's Law equation, so, solving we have:

\frac{V_1}{T_1}=\frac{V_2}{T_2}

We are given:

V_1=350L\\T_1=500K\\T_2=295K

Then, using the Charle's Law equation, we have:

\frac{350L}{500K}=\frac{V_2}{295K}

\frac{350L}{500K}=\frac{V_2}{295K}\\\\V_2=\frac{350L}{500K}*295K=206.5L

Hence, we have that the new volume is equal to 206.5 L.

Have a nice day!

5 0
3 years ago
If you are given the molarity of a solution, what additional information would you need to find the weight/weight percent (w/w%)
Ludmilka [50]

Answer:

- The molar mass of the solute, in order to convert from moles of solute to grams of solute.

- The density of solution, to convert from volume of solution to mass of solution.

Explanation:

Hello,

In this case, since molarity is mathematically defined as the moles of solute divided by the volume of solution and the weight/weight percent as the mass of solute divided by the mass of solution, we need:

- The molar mass of the solute, in order to convert from moles of solute to grams of solute.

- The density of solution, to convert from volume of solution to mass of solution.

For instance, if a 1-M solution of HCl has a density of 1.125 g/mL, we can compute the w/w% as follows:

w/w\%=1\frac{molHCl}{L\ sln}*\frac{36.45gHCl}{1molHCl}*\frac{1L\ sln}{1000mL\ sln}*\frac{1mL\ sln}{1.125g\ sln}    *100\%\\\\w/w\%=3.15\%

Whereas the first factor corresponds to the molar mass of HCl, the second one the conversion from L to mL of solution and the third one the density to express in terms of grams of solution.

Regards.

4 0
3 years ago
Select the correct formula for the polyatomic ion.
Helga [31]
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