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Agata [3.3K]
3 years ago
15

Are the answers correct? if not please help fix them

Chemistry
1 answer:
Serggg [28]3 years ago
8 0

Answer:

Looks like they're all right

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KNO3(s) --> K+(aq) + NO3-(aq)This reaction was carried out in a Styrofoam insulated calorimeter and the following data were r
nataly862011 [7]

Answer:

Equation correctly showing the heat of solution

KNO_3(s)+35.2 kJ \rightarrow K^+(aq) + NO_{3}^-(aq)

Explanation:

Mass of aqueous solution = m = 100 g

Specific heat of solution = c = 4.18 J/gºC

Change in temperature = \Delta T=T_f-T_i

ΔT = 21.6ºC - 30.0ºC = -8.4ºC

Heat lost by the solution = Q

Q = mc\Delta T

Q=100 g\times 4.18 J/g^oC\times (-8.4^oC)

Q = -3,511.2 J ≈ -3.51 kJ

Heat absorbed by potassium nitrate when solution in formed; Q'

Q' = -Q = 3.51 kJ

Moles of potassium nitrate , n= \frac{10.1 g}{101 g/mol}=0.1 mol

KNO_3(s)\rightarrow K^+(aq) + NO_{3}^-(aq)

The heat of solution =

\frac{Q'}{n}=\frac{3.5112 kJ}{0.1 mol}=35.1 kJ/mol

So, the equation correctly showing the heat of solution

KNO_3(s)+35.2 kJ \rightarrow K^+(aq) + NO_{3}^-(aq)

4 0
4 years ago
NEED HELP!!
tester [92]
The answer is (C) 2 hydrogen atoms

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3 years ago
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How many milliliters of sodium metal, with a density of 0.97 g/mL, would be needed to produce 43.6 grams of sodium hydroxide in
GaryK [48]

Answer is: 25.84  milliliters of sodium metal.

Balanced chemical reaction: 2Na + 2H₂O → 2NaOH + H₂.

d(Na) = 0.97 g/mL; density of sodim.

m(NaOH) = 43.6 g; mass of sodium hydroxide.

n(NaOH) = m(NaOH) ÷ M(NaOH).

n(NaOH) = 43.6 g ÷ 40 g/mol.

n(NaOH) =1.09 mol; amount of sodium hydroxide.

From chemical reaction: n(NaOH) : n(Na) = 2 : 2 (1: 1).

n(Na) = 1.09 mol.

m(Na) = 1.09 mol · 23 g/mol.

m(Na) = 25.07 g; mass of sodium.

V(Na) = m(Na) ÷ d(Na).

V(Na) = 25.07 g ÷ 0.97 g/mL.

V(Na) = 25.84 mL.

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4 years ago
Problem 1: For which of the following activities might you want to hire a chemist?
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