Answer:
Carbon, Hydrogen, Oxygen, Nitrogen, and Sulfur.
(Those are all the ones I know)
<span>0.06355391 mol
The balanced equation for the reaction is
Na2B4O7*10H2O + 2 HNO3 = 2 NaNO3 + 4 H3BO3 + 5 H2O
So for each mole of Borax to neutralize, it takes 2 moles of HNO3.
Calculate number of moles of Borax
0.2619 g / 381.372 g/mol = 0.0006867 mol
Moles of HNO3 used = 0.0006867 mol * 2 = 0.0013734 mol
Molarity is defined as moles per liter so divide the number of moles used by the volume in liters. So
0.0013734 / 0.02161 = 0.06355391 mol</span>
NaOH + CH3COOH -> CH3COONa + H20
1.) 28.0 grams of oxygen
28 grams (1 mole/16 grams per mole)=1.75 moles oxygen
2.)5.0 moles of Iron
5 moles(55.845 grams/1 mole)=279.225 grams Iron
3.) 452 grams Argon
452 grams(1 mole/39.948 grams)=11.315 moles Argon
4.) 16.5 moles Hydrogen
16.5 moles(1.01 grams/1 mole)=16.665 grams Hydrogen
Answer:
The answer to your question is No, it is not.
Explanation:
Data
C₄H₁₀ + 13O₂ ⇒ 8CO₂ + 10H₂O
In a double replacement reaction, two reactants interchange cations an example of these reactions are neutralization reactions. In neutralization reactions, an acid and a base react to form a salt and water.
The reaction of this problem is not a double replacement reaction because the products are carbon dioxide and water, not a salt and water.
The reaction of this problem is a combustion reaction.