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anyanavicka [17]
3 years ago
6

The unit of power is derived unit.show how​

Physics
1 answer:
Anna [14]3 years ago
7 0

power=  \frac{work}{time} =  \frac{joule}{second}  = watt

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Physics formula for Celsius to Fahrenheit
worty [1.4K]
F=9/5C+32 is the formula for Celsius to Fahrenheit.
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4 years ago
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You place a 3.0-m-long board symmetrically across a 0.5-m-wide chair to seat three physics students at a party at your house. If
wlad13 [49]

Answer:

  • between locations that are 14 cm outboard of the chair edges
  • the weightless board is centered and end sitters are 25 cm from the ends

Explanation:

We can assume the .5 m-wide chair means that it is comfortable for each student to sit 0.25 m from the end of the board. If the board is centered on the chair, then each student is 1 m from the edge of the chair.

When Dan and Tahreen are seated on the board, their center of mass is ...

  (50 kg×2.5 m)/(50 kg +67 kt) = 1.068 m

to the right of the position where Dan is seated. Since this location is over the chair, the board is stable.

Komila can sit as much as x distance from the chair toward Dan, where ...

  67(1) +54(x) = 50(1.5)

  x = 8/54 ≈ 0.148 . . . . meters

Or, Komila can sit as much as x distance from the chair toward Tahreen, where ...

  67(1.5) = 54(x) +50(1)

  x = 50.5/54 ≈ 0.935 . . . . meters

<u>Scenario 1</u>

Assuming the (weightless) board is centered on the chair, Komila can sit anywhere between 14.8 cm left of the chair and 93.5 cm right of the chair and the board will remain stable. Sitting on the board centered on the chair is a suitable location. The two students sitting on the ends must become (and stay) seated at the same time. They both must be seated 0.25 m from the end of the board for the other dimensions to remain valid.

<u>Scenario 2</u>

Assuming the (weightless) board is located so its left end is 1.068 m from the chair, and Dan and Tahreen are seated 0.25 m from the ends of the board, Komila can sit anywhere within (117/54×.25 m) = 0.54 m of the chair and the board will remain stable. Again, sitting centered on the chair is a suitable location.

__

There does not appear to be any location where Komila can sit and have the board remain stable with only Dan or Tahreen seated on one end (assuming a width of 0.5 m for each sitter).

_____

<em>Comment on the question</em>

For the board to remain stable, the sum of moments about either edge of the chair must tend to rotate the board toward the chair. This sum will depend on the locations of the sitters relative to each edge of the chair, so there is significant freedom in choosing locations. To make the problem tractable, we have made some specific assumptions about where the board is and what the locations of the sitters might be. YMMV

3 0
4 years ago
A bullet is fired straight up from ground level for a distance of 1688.3m at a speed of 182 m/s. How long does it take for the b
Vitek1552 [10]
S= 1/2 x 182 x t = 1688.3
t = 1688.3 / 91
time = 18.55 seconds
3 0
3 years ago
A member of the Penn State Women's Basketball team performs a jumping movement simulating that used in a jump shot. The time fro
Shkiper50 [21]

A) Starting from rest, we have the entire cycle determined by 0.8s.

If we assume a constant movement, half of that time is when it reaches the highest point, that is, in 0.4s.

The distance as a function of speed and acceleration is given by,

d=v_it+\frac{1}{2}at^2

At the initial point the speed is zero and the acceleration is equivalent to gravity.

d= 0+ \frac{1}{2}9.8*0.4^2

d=0.784m

B) When returning to the ground, the final speed is zero. Therefore, the equation that relates velocity to acceleration is given by,

V_f = V_i+at

0 = V_i -9.8(0.4)

V_i = 3.92m/s

5 0
4 years ago
How does a decrease in thermal energy affect the kinetic energy of the particles in each state of matter?
Svetlanka [38]

Answer:

kinetic and potential energy). The opposite is true when you remove thermal energy: Particles move slower (less kinetic energy). Particles get closer together (less potential energy)

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3 years ago
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