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Grace [21]
2 years ago
8

Seismic waves do not travel along the Earth’s surface. Please select the best answer from the choices provided T F.

Physics
1 answer:
zysi [14]2 years ago
7 0

Seismic waves do not travel along the Earth’s surface. The statement is false.

<h3>what are seismic waves?</h3>

The seismic waves can be defined as the waves full of energy that travel through the Earth's layer, these waves are the result of earthquake.

They can further be divided into two types body wave and surface waves. The body waves travel in the interior of the Earth and the surface waves travel at the surface of the Earth.

The seismic waves can have an amplitude of few centimeters in large earthquake. They travel slower as compared to the body waves.

Hence Seismic waves do not travel along the Earth’s surface. The statement is false.

To know more about Seismic waves follow

brainly.com/question/6835759

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Answer:

D. has no overall force acting on it.

Explanation:

Why?

Because in a straight line at the constant speed means the car moving in the same velocity, which is not acceleration neither deceleration, and it cannot be on a downhill slope. So the correct answer is

<h3>→ D. has no overall force acting on it.</h3>
8 0
3 years ago
Define potential energy (PE)
Umnica [9.8K]

Answer:

Potential energy is the energy that exists by virtue of the relative positions (configurations) of the objects within a physical system.

This form of energy has the potential to change the state of other objects around it, for example, the configuration or motion.

Various forms of energy can be grouped as potential energy.

Each of these forms is associated with a particular kind of force acting in conjunction with some physical property of matter (such as mass, charge, elasticity, temperature etc).

For example, gravitational potential energy is associated with the gravitational force acting on object's mass; elastic potential energy with the elastic force (ultimately electromagnetic force) acting on the elasticity of a deformed object; electrical potential energy with the coulombic force; strong nuclear force or weak nuclear force acting on the electric charge on the object; chemical potential energy, with the chemical potential of a particular atomic or molecular configuration acting on the atomic/molecular structure of the chemical substance that constitutes the object; thermal potential energy with the electromagnetic force in conjunction with the temperature of the object.

For an example of gravitational potential energy, consider a book placed on top of a table.

To raise the book from the floor to the table, work must be done, and energy supplied. (If the book is lifted by a person then this is provided by the chemical energy obtained from that person's food and then stored in the chemicals of the body.) Assuming perfect efficiency (no energy losses), the energy supplied to lift the book is exactly the same as the increase in the book's gravitational potential energy.

The book's potential energy can be released by knocking it off the table.

As the book falls, its potential energy is converted to kinetic energy.

When the book hits the floor this kinetic energy is converted into heat and sound by the impact.

Explanation:

4 0
3 years ago
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prohojiy [21]
This is caused my a magic illusion and when you stand at a certain angle in themirror it changes your image
8 0
3 years ago
BRAINLIEST. Agraph is probelow. The graph shows the speed of a car traveling east over a 12 second period. Based on the informat
gavmur [86]

Answer: Speeding up constantly

Explanation:

3 0
4 years ago
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If two metal balls each have a charge of -10^-6 C and the repulsive force between them is 1 N, how far apart are they? (Coulomb'
Vitek1552 [10]

Answer:

The distance between the charges is 9.5 cm

(c) is correct option

Explanation:

Given that,

Charge q= 10^{-6}\ C

Force F = 1 N

We need to calculate the distance between the charges

Using Coulomb's formula

F = \dfrac{kq_{1}q_{2}}{r^2}

Where, q = charge

r = distance

F = force

Put the value into the formula

1=\dfrac{9.0\times10^{9}\times(-10^{-6})^2}{r^2}

r=\sqrt{9\times10^{9}\times(-10^{-6})^2}

r=0.095\ m

r= 9.5\ cm

Hence, The distance between the charges is 9.5 cm

4 0
3 years ago
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