The weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosphere is, 4.56*10^5N.
To find the answer, we have to know about the pressure.
<h3>How to find the weight of a column of air?</h3>
- As we know that the expression of pressure as,
where; F is the force, here it is equal to the weight of the air column, and A is the area of cross section.
- It is given that, the air column is extending from earth's surface to the top of the atmosphere, thus, the pressure will be atmospheric pressure,
- From this, the value of weight will be,
Thus, we can conclude that, the weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosphere is, 4.56*10^5N.
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Answer: The magnetic field lines go in directions that cannot combine to form a magnetic field between the two north poles.
Explanation: that was the answer for me I just took it on ape x
This question involves the concept of Colomb's Law and electrostatic force.
The electrostatic force will be "0.2 N".
<h3>COLOMB'S LAW:</h3>
According to Colomb's Law, every charge exerts an electrostatic force on the other charge, which is directly proportional to the product of the magnitudes of both the charges and inversely proportional to the square of the distance between them.
where,
- F = electrostatic force
- k = Colomb's constant = 9 x 10⁹ N.m²/C²
- q₁ = magnitude of first charge
- q₂ = magnitude of second charge
- r = distance between charges
In case of +2 C charges:
- q₁ = q₂ = 2 C
- r = ?
- F = 0.1 N
Therefore,
Now, for the second case:
- F = ?
- q₁ = 2 C
- q₂ = 4 C
- r² = 3.6 x 10¹¹ m²
Therefore,
<u>F = 0.2 N</u>
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Responda:
9.2s
Explicação:
Dada a pergunta:
Em quanto tempo o um paraquedista, em queda livre, atinge a velocidade de 90 m / s?
Em queda livre; a aceleração de um corpo = 9,8m / s ^ 2
Portanto, quanto tempo leva para atingir uma velocidade de 90 m / s
Da primeira equação de movimento:
v = u + em
v = velocidade final; u = velocidade inicial; a = aceleração; t = tempo
90 = 0 + 9,8t
90 = 9,8t
t = 90 / 9,8
t = 9,18s = 9,2 s
