Using the velocity-time graph, the displacement can be calculated by the area under the velocity-time graph. At 3 seconds the total displacement is then equal to (4)(2) + (4 + 2)*1/2 = 11 m. Assuming that the starting point is at x = 0, then the particle at t=3s is at x=11 m.
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
Answer:
The right answer is 8.9 x 10^-3 M/min
Explanation:
A → B
-d [A]/dt = K [A]
ΔA/Δt = - (C2 -C1)/t2 - t1
= - (0.11 - 0.91)/90
= 8.9 x 10^-3 M/min
<span>PV is actually energy. P = F/A force per area, and V = A L, so PV = F L and force times distance is work which is energy. If you have P in N/m^2 and V in m^3, you have Joules, N-m.</span>
It’s 21 c it all on the weather outside but most of the time it’s on 21
