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miskamm [114]
3 years ago
13

Hypobromite is used to purify contaminated water. What is the formula for hypobromite?

Chemistry
1 answer:
sertanlavr [38]3 years ago
4 0
 Best Answer:<span>  </span><span>Bromate ion is BrO₃⁻. 
In each hypobromite ion, there are 2 oxygen atom less than bromated ion. 
Therefore, hypobromite ion is BrO⁻. 

...... The answer is : a. BrO⁻

</span>
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irinina [24]

Answer:

because it's shellfish

Explanation:

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3 years ago
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Water is composed of one atom of oxygen and two atoms of
egoroff_w [7]

Answer:

<em>Hydrogen.</em>

Explanation:

You've probably seen "H_{2}0" which is the formula for water. It means that there's 2 hydrogen atoms, and one oxygen atom, in one molecule of water.

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The amount of protein in a sample was measured by the sample's absorbance of light at a given wavelength. Using standards, a bes
FinnZ [79.3K]

Answer:

Protein Concentration is 2.82mg/L

Explanation:

According to Beer-Lambert's Law, Absorbance is directly proportional to the concentration.

However, the concentration of a solution can be determined from a calibration curve, in which Absorbance is plotted on the y-axis and the Concentration on the x-axis.

Plotting the best line, the equation of line is used

y = mx + c

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inserting the values from the question

y = mx + c

0.150 = 0.0163x + 0.104

0.0163x = 0.150 - 0.104

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5 0
3 years ago
Consider the following chemical reaction: 2KCl + 3O2 --&gt; 2KClO3. If you are given 100.0 moles of KCl and 100.0 moles of O2...
g100num [7]

Answer:

O₂; KCl; 33.3  

Explanation:

We are given the moles of two reactants, so this is a limiting reactant problem.

We know that we will need moles, so, lets assemble all the data in one place.

            2KCl  +  3O₂ ⟶ 2KClO₃

n/mol:  100.0   100.0

1. Identify the limiting reactant

(a) Calculate the moles of KClO₃ that can be formed from each reactant

(i)From KCl

\text{Moles of KClO}_{3} = \text{100.0 mol KCl} \times \dfrac{\text{2 mol KClO}_{3}}{\text{2 mol KCl}} = \text{100.0 mol KClO}_{3}

(ii) From O₂

\text{Moles of KClO}_{3} = \text{100.0 mol O}_{2} \times \dfrac{\text{2 mol KClO}_{3}}{\text{3 mol O}_{2}} = \text{66.67 mol KClO}_{3}

O₂ is the limiting reactant, because it forms fewer moles of the KClO₃.

KClO₃ is the excess reactant.

2. Moles of KCl left over

(a) Moles of KCl used

\text{Moles used} = \text{100.0 mol O}_{2} \times \dfrac{\text{2 mol KCl}}{\text{3 mol O}_{2}} = \text{66.67 mol KCl}

(b) Moles of KCl left over

n = 100.0 mol - 66.67 mol = 33.3 mol

3 0
3 years ago
Can a molecule with nonpolar bonds ever be polar? Why<br> why not?
Tanya [424]

Answer:

A molecule that has only nonpolar bonds and no polar bonds cannot be polar.

Explanation:

However, a molecule that CONTAINS nonpolar bonds is different, because it can contain polar bonds. A molecule that contains nonpolar bonds can be polar as long as it also contains polar bonds.

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2 years ago
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