The law of conservation of angular momentum.
What is angular momentum?
Angular momentum is the rotational analog of linear momentum in physics. It is a conserved quantity, meaning the total angular momentum of a closed system remains constant. Both the direction and magnitude of angular momentum are conserved.
What is the law of conservation of angular momentum?
The law of conservation of angular momentum asserts that a system's total angular momentum is conserved when there is no external torque present. In other words, the magnitude and direction of the total angular momentum of an isolated system remain constant.
According to the Nebular Theory, the solar system originated as a massive, slowly rotating cloud of gas measuring around one light-year in diameter. As the cloud cooled, its own gravity caused it to collapse. It distorted into a revolving pancake shape due to the conservation of angular momentum, which required it to spin faster as it shrank.
Hence, the law of conservation of angular momentum best explains why the solar nebula spun faster as it shrank in size.
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Because Mars is too far away for its gravitational pull to affect us, in addition Earths gravitational pull is greater than Mars anyways.
The magnitude of the resultant is
√ (22² + 2.2²) = √ (484 + 4.84) = √488.84 = 22.11 m/s .
The direction of the resultant is
tan⁻¹(22N / 2.2E) = tan⁻¹(10) = 5.71° east of north .
Answer:
a) There are 100 centimeters in 1 meter.
b) 
Explanation:
a) We have the conversion
1 m = 100 cm
So there are 100 centimeters in 1 meter.
b) 1 inch = 2.54 cm
Answer:
0.3 m
Explanation:
Initially, the package has both gravitational potential energy and kinetic energy. The spring has elastic energy. After the package is brought to rest, all the energy is stored in the spring.
Initial energy = final energy
mgh + ½ mv² + ½ kx₁² = ½ kx₂²
Given:
m = 50 kg
g = 9.8 m/s²
h = 8 sin 20º m
v = 2 m/s
k = 30000 N/m
x₁ = 0.05 m
(50)(9.8)(8 sin 20) + ½ (50)(2)² + ½ (30000)(0.05)² = ½ (30000)x₂²
x₂ ≈ 0.314 m
So the spring is compressed 0.314 m from it's natural length. However, we're asked to find the additional deformation from the original 50mm.
x₂ − x₁
0.314 m − 0.05 m
0.264 m
Rounding to 1 sig-fig, the spring is compressed an additional 0.3 meters.
