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Rasek [7]
3 years ago
14

Please answer these for the brainliest

Chemistry
2 answers:
k0ka [10]3 years ago
8 0
Magnetic attraction and evaporation are the answers
Ira Lisetskai [31]3 years ago
8 0

Answer:

B

Explanation:

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List any two uses of Brass , Bronze , Sulphur , Iodine
NikAS [45]

BRASS :It is easy to form into various shapes, a good conductor of heat, and generally resistant to corrosion from salt water. 1 pipes and 2 tubes, 3 screws, 4 cartridge casings for firearms.

BRONZE :for bearings because of its friction properties, and as 1 musical instruments ,2 and medals

Sulphur :1 making car batteries, 2 fertilizer

IODINE :1 Iodine regulates skin moisture levels and aids in the healing of cuts and scars through cellular regeneration. 2 Iodine also regulates the hormones responsible for acne breakouts.3 Treating thyroid cancer.

5 0
3 years ago
A sugar solution is 15% pure. How
Arada [10]

Answer:

Amount of sugar in solution = 82.5 gram

Explanation:

Given:

Sugar in solution percentage = 15%

Total solution = 550 grams

Find:

Amount of sugar in solution

Computation:

Amount of sugar in solution = Sugar in solution percentage x Total solution

Amount of sugar in solution = 15% X 550

Amount of sugar in solution = 82.5 gram

8 0
3 years ago
What is the value of k for this aqueous reaction at 298 k?
TEA [102]

Answer : The complete question is attached in answer.

The value of K will be = 2 X10^{-5}


Explanation : We can use the formula as;


∆G = -RT ln K


on rearranging we get, K = e^({-deltaG/RT})

Therefore, we get,

∆G/RT = (26.81 kJ/mol ) / (0.008314 kJ/mol-K) X (298K) = 10.82


So, K = e^{-10.82}

Therefore, K = 2 X 10^{-5}

5 0
3 years ago
A patient receives 3.3 L of glucose solution intravenously (IV). If 100. mL of the solution
artcher [175]

Answer:

660kcal

Explanation:

The question is missing the concentration of the glucose solution. Standard glucose concentration for IV solution is 5% or 5g of glucose every 100mL of solution.  

We need to determine how many grams of glucose are there inside the solution. The number of glucose in 3.3L solution will be:  

3.3L * (1000mL / L) * (5g/100mL)= 165 g.

If glucose will give 4kcal/ g, then the total calories 165g glucose give will be: 165g * 4kcal/ g= 660kcal.

6 0
4 years ago
Use the following chemical equation to answer the question.
AVprozaik [17]

Answer:14,5 grams of K2O

Explanation:

4 0
3 years ago
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