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3 years ago

A sugar solution is 15% pure. How

Chemistry

1 answer:

Arada [10]3 years ago

8 0

Answer:

Amount of sugar in solution = 82.5 gram

Explanation:

Given:

Sugar in solution percentage = 15%

Total solution = 550 grams

Find:

Amount of sugar in solution

Computation:

Amount of sugar in solution = Sugar in solution percentage x Total solution

Amount of sugar in solution = 15% X 550

Amount of sugar in solution = 82.5 gram

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Answer:

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Explanation:

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3 years ago

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3 years ago

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4 years ago

100 cm3 of the copper sulfate solution contains 1.8 g of copper sulfate.

elixir [45]

Answer:

The mass of copper sulfate in 25 cm³ of the copper sulfate solution is 0.45 g

Explanation:

The given parameters are;

The volume of the copper sulfate solution = 100 cm³

The mass of the copper sulfate in the solution = 1.8 g

Therefore, the mass of copper sulfate in 25 cm³ of the solution is given as follows;

The mass of copper sulfate in 100 cm³ of the solution = 1.8 g

The mass of copper sulfate in 1 cm³ of the solution = 1.8 g/100 = 0.018 g

Therefore;

The mass of copper sulfate in 25 × 1 = 25 cm³ of the solution, m = 25×0.018 g = 0.45 g

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8 0

3 years ago

When fluorine gas combines with water vapor, the following reactions occurs.

jonny [76]

Hello!

The Chemical reaction is the following:

2F₂(g) + 2 H₂O(g) → O₂(g) + 4HF(g)

If we assume that all the gases are ideal gases, we can describe the coefficients of this reaction as Volume rather than moles, so we can apply the following equations:

$2 L F_2* \frac{2 L H_2O}{2 L F_2}=2 L H_2O \\ \\ 2 L F_2* \frac{1 mol O_2}{2 L F_2}=1 mol O_2 \\ \\ 2 L F_2* \frac{4 mol HF}{2 mol F_2}= 4 mol HF$

So, 2 L of Water Vapor reacts with the fluorine; and 1 L of Oxygen and 4 L of Hydrogen Fluoride are produced.

Have a nice day!

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3 years ago