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zheka24 [161]
3 years ago
12

What is the molecular geometry if you have a double bond, a single bond and 1 lone pair around the central atom?What is the mole

cular geometry if you have a double bond, a single bond and 1 lone pair around the central atom?
Mathematics
1 answer:
Fiesta28 [93]3 years ago
5 0

Answer:

Bent Molecular Geometry.

Step-by-step explanation:

For the explanation Ozone (O_3) can be used as it has 1 lone pair and 2 bonded pairs containing 1 double bond and 1 single bond. According to Valence Shell Electron Pair Repulsion Theory as lone pairs have the highest repulsion they will push the bond pairs away, thereby creating a bent shape with an angle of less than 120° (around 116°).

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Step-by-step explanation:

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Evaluate the expression when a = 3, b = 2, and c= -3: (a³ + 2bc)/( c² -5)
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((3*3*3)+2(-6))/((-3*-3)-5)
(27-12)/9-5
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A person is standing close to the edge on a 56 foot building and throws the ball vertically upward. The quadratic function h(t)=
Romashka [77]

Answer:

Part 1)

225 feet.

Part 2)

7 seconds.

Step-by-step explanation:

The height h(t) of the ball above the ground after <em>t</em> seconds is modeled by the function:

h(t)=-16t^2+104t+56

Part 1)

We want to determine the maximum height of the ball.

Notice that the function is a quadratic with a negative leading coefficient, so its maximum will be at its vertex point.

The vertex of a parabola is given by:

\displaystyle \text{Vertex} = \left(-\frac{b}{2a}, f\left(-\frac{b}{2a}\right)\right)

In this case, <em>a</em> = -16, <em>b</em> = 104, and <em>c</em> = 56.

Find the <em>x-</em> (or rather <em>t-</em>)<em> </em>coordinate of the vertex. So:

\displaystyle t=-\frac{(104)}{2(-16)}=\frac{104}{32}=\frac{13}{4}=3.25\text{ seconds}

In other words, the ball reaches its maximum height after 3.25 seconds.

To find the maximum height, substitute this value back into the function. Hence:

\displaystyle h(3.25)=-16(3.25)^2+104(3.25)+56=225\text{ feet}

The maximum height of the ball is 225 feet in the air.

Part 2)

We want to find the amount of time it took for the ball to hit the ground.

When the ball hit the ground, its height above the ground is zero. Therefore, we can set h(t) to 0 and solve for <em>t: </em>

0=-16t^2+104t+56

We can simplify a bit. Divide both sides by -8:

0=2t^2-13t-7

We can factor. Find two numbers that multiply to 2(-7) = -14 and add to -13.

-14 and 1 works! Therefore, split the second term into -14 and 1:

\displaystyle 0=2t^2-14t+t-7

Factor out a 2<em>t</em> from the first two terms and group the last two terms:

0=2t(t-7)+(t-7)

Factor by grouping:

0=(2t+1)(t-7)

Zero Product Property:

2t+1=0\text{ or } t-7=0

Solve for each case:

\displaystyle t=-0.5\text{ or } t=7

Since time cannot be negative, we can ignore the first case.

Therefore, it takes seven seconds for the ball to hit the ground.

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What number on the number line represents ground level?<br>0<br>-1<br>-2<br>-3<br>-4<br>-5<br>-6​
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Answer:

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Step-by-step explanation:

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