Answer:
1.99 x 10²³ formula units
Explanation:
Given parameters:
Mass of AgF = 42.15g
Unknown:
The amount of formula units
Solution:
To solve this problem, we set out by find the number of moles in this compound from the given mass.
Number of moles = 
molar mass of AgF = 107.9 + 19 = 126.9g/mol
Number of moles = 
= 0.33 moles
1 mole of a substance = 6.02 x 10²³ formula units
0.33 moles of AgF = 0.33 x 6.02 x 10²³ = 1.99 x 10²³ formula units
Molar mass ( CuSO₄) = 159.609 g/mol
159.609 g ----------------- 6.02 x 10²³ molecules
? g ------------------ 3.36 x 10²³ molecules
mass = ( 3.36 x10²³) x 159.609 / 6.02 x 10²³
mass = 5.36 x 10²⁴ / 6.02 x 10²³
mass = 8.90 g
hope this helps!
The mass of iron (III) oxide (Fe2O3) : 85.12 g
<h3>Further explanation</h3>
Given
3.20x10²³ formula units
Required
The mass
Solution
1 mole = 6.02.10²³ particles
Can be formulated :
N = n x No
N = number of particles
n = mol
No = 6.02.10²³ = Avogadro's number
mol of Fe₂O₃ :
mass of Fe₂O₃ (MW=160 g/mol)
Answer:
The Moon's surface is dominated by igneous rocks. The lunar highlands are formed of anorthosite, an igneous rock predominantly of calcium-rich plagioclase feldspar
Explanation:
