Which of the following models shows how unpredictable electrons are?

Physics

2 answers:

777dan777 [17]3 years ago

8 0

Answer:

on edge

Explanation:

Fantom [35]3 years ago

7 0

The exact location of electrons in electron shells of atoms cannot be exactly ascertained. This is why VSPER atomic models represent the position of electrons (s, p, d, & f) using the probability of where they would most be expected to be found.

Explanation:

This is because merely observing electrons changes their behavior. Remember that to observe something one has to shine light on it so it bounces back to the eye. Due to the negligible mass of electrons, mere photons of light will change their direction of movement, spin or other behaviors/properties.

Learn More:

For more on electron clouds check out;

brainly.com/question/12199882

brainly.com/question/11686000

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Times will the kinetic one

mixer [17]

Answer:

The new kinetic energy is 9 times of the initial kinetic energy.

Explanation:

The kinetic energy of an object is given by the formula as follows :

$E=\dfrac{1}{2}mv^2$

Where

m is mass and v is speed of the body

If the speed of the body is tripled. Let v' is the new speed, v' = 3v. The new kinetic energy is E' and it is given by :

$E'=\dfrac{1}{2}mv'^2\\\\\text{Put v' = 3v}\\\\E'=\dfrac{1}{2}m\times (3v)^2\\\\=\dfrac{1}{2}m\times 9v^2\\\\=9\times (\dfrac{1}{2}mv^2)\\\\E'=9\times E$

Hence, the new kinetic energy is 9 times of the initial kinetic energy.

3 0

3 years ago

A mass of 25.5 g of H2O(g) at 373 K is mixed with 325 g of H2O(l) at 285 K and 1 atm. Calculate the final temperature of the sys

Vedmedyk [2.9K]

Answer:

331.28 K

Explanation:

To solve this problem, you need to know that the heat that the water at 373 K is equal to the heat that the water at 285 K gains.

First, we will asume that at the end of this process there won't be any water left in gaseous state.

The heat that the steam (H20(g)) loses is equal to the heat lost because the change of phase plus the heat lost because of the decrease in temperature:

$Q_g = c_l*m_{wg} + m_{wg}*c*(T_{og}-T{fg})$

The specific Heat c of water at 298K is 4.18 kJ/K*kg.

The latent heat cl of water is equal to 2257 kJ/kg.

The heat that the cold water gains is equal to heat necessary to increase its temperature to its final value:

$Q_l = m_{wl}*c*(T_{fl}-T_{ol})$

Remember that in equilibrium, the final temperature of both bodies of water will be equal.

Then:

$Q_g = Q_l\\c_l*m_{wg} + m_{wg}*c*(T_{og}-T{fg}) = m_{wl}*c*(T_{fl}-T_{ol})\\2257 kJ/kg*0.0255 kg + 0.0255 kg*4.18 kJ/kg*K*(373K - T_f) = 0.325 kg*4.18kJ/kg*K*(T_f-285K)\\57.5535 kJ + 39.75807kJ - 0.10659T_f = 1.3585 T_f - 387.1725 kJ\\484.48407 kJ = 1.46244 T_f\\T_f = 484.48407 kJ /1.46244 = 331.28 K$